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01 Mar 2018, 00:51
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
15%
(low)
Question Stats:
82% (01:44) correct
18%
(02:11)
wrong
based on 189
sessions
History
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Time
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Not Attempted Yet
The heights of the five starters on Redwood High's basketball team are 5'11" (5 feet 11 inches), 6'3", 6', 6'6", and 6'2". The average height of these players is
(1 foot = 12 inches)
(A) 6'1"
(B) 6'2"
(C) 6' 3"
(D) 6'4"
(E) 6'5"
(1 foot = 12 inches)
(A) 6'1"
(B) 6'2"
(C) 6' 3"
(D) 6'4"
(E) 6'5"
01 Mar 2018, 00:52
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01 Mar 2018, 01:18
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Bunuel
The best way to do this problem is to convert the respective heights into inches
and finding the average, since the answers for the average height are very close!
When converted in inches, we will get 71,72,74,75, and 78 inches.
The average is \(\frac{70*5}{5} + \frac{1+2+4+5+8}{5} = 70 + \frac{20}{5} = 74\) inches, which is 6' 2"(Option B)
