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Bunuel
If k is a positive integer such that 5,880k is a perfect square, what is the least possible value of k?

(A) 2
(B) 6
(C) 15
(D) 30
(E) 140

Bunuel there seems something wrong with the question. Is the integer at hand 5,880*k or 5,880k which is a concatenation of 5,880 & k. Is this an ambiguity or am I making a mistake in reading it properly.

Please advise.

Best,
Gladi

5,880k is 5,880*k, so 5,880 multiplied by k (also recall that multiplication sign is often omitted). It cannot be a five-digit integer 5880k because if it were it would have been explicitly mentioned.
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Bunuel
If k is a positive integer such that 5,880k is a perfect square, what is the least possible value of k?

(A) 2
(B) 6
(C) 15
(D) 30
(E) 140


We are given that 5,880k is a perfect square. We must remember that all perfect squares break down to unique prime factors, each of which has an exponent that is a positive multiple of 2. So, let’s break down 5,880 into its prime factors to determine the minimum value of k.

5,880 = 588 x 10 = 12 x 49 x 10 = 2^3 x 3^1 x 5^1 x 7^2

So, in order for 5,880k to be a perfect square, k must contain the factors 2 x 3 x 5 = 30 (so that 5,880k = 2^4 x 3^2 x 5^2 x 7^2), so 30 is the smallest possible value of k.

Answer: D
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Solution



    • \(5880* k\) can be written in prime factorization form as \(2^3 * 3 *5 * 7^2 * k\).

    • Since \(5880 * k\) is a perfect square, hence \(5880 * k=n^2\), where \(n\) is any integer.
      o \(n^2 = 2^3 * 3 * 5 * 7^2 * k\)

      o After taking square root on both the sides, we can write:
        o \(n= 2*7* \sqrt{(2*3*5*k)}\)
        oFor \(n\) to be an integer,\(\sqrt{(2 * 3 * 5 * k)}\) must be a perfect square.
          oHence,\(k = 2 * 3 * 5 *\) (square of any positive integer)
      .

    • The least possible value of the square of a positive integer is 1.
      o Hence, k=2 * 3 * 5 = 30
    .

Answer: D
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Bunuel
If k is a positive integer such that 5,880k is a perfect square, what is the least possible value of k?

(A) 2
(B) 6
(C) 15
(D) 30
(E) 140

The rule says, " A perfect square always has even number of powers of prime factors".

Prime factorisation of 5880 = 2^3*3^1*5^1*7^2

Therefore, to make 5880 a perfect square we need to multiply it by a set of 2*3*5 = 30

Hence (D)
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