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26 Mar 2018, 00:32
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
15%
(low)
Question Stats:
79% (01:00) correct
21%
(01:05)
wrong
based on 111
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What is the probability that a randomly selected integer from a list of consecutive integers from 101 to 500, inclusive will have a hundreds digit of 3?
(A) 1/5
(B) 1/4
(C) 1/3
(D) 2/5
(E) 3/4
(A) 1/5
(B) 1/4
(C) 1/3
(D) 2/5
(E) 3/4
26 Mar 2018, 02:01
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Bunuel
Since the calculation we're required to do is straightforward, we'll just do it.
This is a Precise approach.
There are 400 integers between 101 to 500 inclusive of which exactly 100 (from 300 to 399, inclusive) have a hundreds digit of 3.
This gives a probability of 100/400 = 1/4.
(B) is our answer.
26 Mar 2018, 08:15
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Bunuel
Possible outcomes: 400
Possible: All integers from 101 to 500
(500 - 101) = 399 +1 = 400
Favorable outcomes: 100
Favorable: All the 300s. (399-300)= 99 + 1= 100
\(\frac{Favorable}{Possible}=\frac{100}{400}=\frac{1}{4}\)
Answer B
*Inclusive counting ("add one before you're done") can create confusion. Inclusive counting: (Highest - lowest) + 1. If unsure in the moment, test with small numbers.
Ex.: How many integers from 1 to 4? List them: 1, 2, 3, 4. Count. There are four integers from 1 to 4.
Then: (4-1)= 3. Not correct. ADD 1. (3+1) = 4
