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Bunuel
A collection of U.S. coins consists of pennies, nickels, dimes, and quarters, in the ratio 2:3:5:6, respectively. If the number of coins of one of the denominations is 30, which of the following CANNOT be the total number of coins in the collection?
6
(A) 80
(B) 96
(C) 112
(D) 160
(E) 240


Since the ratio of the collection is 2:3:5:6,
the total coins in the collection must be 2x + 3x + 5x + 6x or 16x.

Since the number of coins of one of the denominators is 30, either 2x,3x,5x, or 6x must be 30.

If 2x = 30 -> x = 15. 16x = 240
If 3x = 30 -> x = 10. 16x = 160
If 5x = 30 -> x = 6. 16x = 96
If 6x = 30 -> x = 5. 16x = 80

Only Option C(112) CANNOT be the total number of coins in the collection.
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pushpitkc
Bunuel
A collection of U.S. coins consists of pennies, nickels, dimes, and quarters, in the ratio 2:3:5:6, respectively. If the number of coins of one of the denominations is 30, which of the following CANNOT be the total number of coins in the collection?

(A) 80
(B) 96
(C) 112
(D) 160
(E) 240


Since the ratio of the collection is 2:3:5:6,
the total coins in the collection must be 2x + 3x + 5x + 6x or 16x.

Evaluating answer options,
(A) 80 = 16*5
(B) 96 = 16*6
(C) 112 is not divisible by 16
(D) 160 = 16*10
(E) 240 = 16*15

Only Option C(112) CANNOT be the total number of coins in the collection.
pushpitkc and maybe gmatbusters . . .

16*7 = 112

:?
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gmatbusters
The ratio is 2:3:5:6
Let the coins are 2x,2x 3x, 5x, 6x.
Total = 16x

Since one of the coin is 30.
X can be 15, 20, 6, 5.
Hence total can be 16x = 240, 320, 96 or 80.

Hence total cannot be 112. Answer is C
gmatbusters , I don't follow your steps.

What are your steps, please?

And is
Quote:
Let the coins are 2x,2x 3x, 5x, 6x

that part a typo?
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Since the ratio is given we can suppose the no of coins as 2x,3x,5x,6x.total =16x

If 2x =30
We get x = 15

Total = 15*16 = 240. Hence 240 is possible.

Similarly for other cases.


We find that x is not equal to 7. Hence 112 is not possible.

Hope it is clear now.

generis
gmatbusters
The ratio is 2:3:5:6
Let the coins are 2x,3x, 5x, 6x.
Total = 16x

Since one of the coin is 30.
X can be 15, 20, 6, 5.
Hence total can be 16x = 240, 320, 96 or 80.

Hence total cannot be 112. Answer is C
gmatbusters , I don't follow your steps.

What are your steps, please?

And is
Quote:
Let the coins are 2x,2x 3x, 5x, 6x

that part a typo?

Posted from my mobile device
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Yes you are right.2x has been written twice inadvertently. it is a typo. Tganks for pointing out.

I revised it.

generis
gmatbusters
The ratio is 2:3:5:6
Let the coins are 2x,2x 3x, 5x, 6x.
Total = 16x

Since one of the coin is 30.
X can be 15, 20, 6, 5.
Hence total can be 16x = 240, 320, 96 or 80.

Hence total cannot be 112. Answer is C
gmatbusters , I don't follow your steps.

What are your steps, please?

And is
Quote:
Let the coins are 2x,2x 3x, 5x, 6x

that part a typo?

Posted from my mobile device
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We find that if total is 112,which is 16*7 doesnt gives any number of coin as 30.

If we take 112 as total, and ratio as 2:3:5:6.
Then the coins will be
2*112/(2+3+5+6) =14,
3*112/(2+3+5+6) =21,
5*112/(2+3+5+6) =35,
6*112/(2+3+5+6) =42.

No denomination is present as 30 numbers. which is against the question.

Hence 112 is not the total number of coins.


generis
pushpitkc
Bunuel
A collection of U.S. coins consists of pennies, nickels, dimes, and quarters, in the ratio 2:3:5:6, respectively. If the number of coins of one of the denominations is 30, which of the following CANNOT be the total number of coins in the collection?

(A) 80
(B) 96
(C) 112
(D) 160
(E) 240


Since the ratio of the collection is 2:3:5:6,
the total coins in the collection must be 2x + 3x + 5x + 6x or 16x.

Evaluating answer options,
(A) 80 = 16*5
(B) 96 = 16*6
(C) 112 is not divisible by 16
(D) 160 = 16*10
(E) 240 = 16*15

Only Option C(112) CANNOT be the total number of coins in the collection.
pushpitkc and maybe gmatbusters . . .

16*7 = 112

:?

Posted from my mobile device
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This approach is not applicable to this question, as all the options are multiple od 16.

pushpitkc
Bunuel
A collection of U.S. coins consists of pennies, nickels, dimes, and quarters, in the ratio 2:3:5:6, respectively. If the number of coins of one of the denominations is 30, which of the following CANNOT be the total number of coins in the collection?

(A) 80
(B) 96
(C) 112
(D) 160
(E) 240


Since the ratio of the collection is 2:3:5:6,
the total coins in the collection must be 2x + 3x + 5x + 6x or 16x.

Evaluating answer options,
(A) 80 = 16*5
(B) 96 = 16*6
(C) 112 is not divisible by 16
(D) 160 = 16*10
(E) 240 = 16*15

Only Option C(112) CANNOT be the total number of coins in the collection.

Posted from my mobile device
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generis
pushpitkc
Bunuel
A collection of U.S. coins consists of pennies, nickels, dimes, and quarters, in the ratio 2:3:5:6, respectively. If the number of coins of one of the denominations is 30, which of the following CANNOT be the total number of coins in the collection?

(A) 80
(B) 96
(C) 112
(D) 160
(E) 240


Since the ratio of the collection is 2:3:5:6,
the total coins in the collection must be 2x + 3x + 5x + 6x or 16x.

Evaluating answer options,
(A) 80 = 16*5
(B) 96 = 16*6
(C) 112 is not divisible by 16
(D) 160 = 16*10
(E) 240 = 16*15

Only Option C(112) CANNOT be the total number of coins in the collection.
pushpitkc and maybe gmatbusters . . .

16*7 = 112

:?

Thanks for informing generis - Corrected my solution!
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Bunuel
A collection of U.S. coins consists of pennies, nickels, dimes, and quarters, in the ratio 2:3:5:6, respectively. If the number of coins of one of the denominations is 30, which of the following CANNOT be the total number of coins in the collection?

(A) 80
(B) 96
(C) 112
(D) 160
(E) 240

We can create the ratio of pennies : nickels : dimes : quarters = 2x : 3x : 5x : 6x

So the total number of coins is 16x.

If there are 30 pennies, then x = 15 and 16x = 240.

If there are 30 nickels, then x = 10 and 16x = 160.

If there are 30 dimes, then x = 6 and 16x = 96.

If there are 30 quarters, then x = 5 and 16x = 80.

Thus, 112 cannot be the total number of coins.

Answer: C
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