Letters of the word BOSTON are shuffled to form six-letter word. In ho

Question

Letters of the word BOSTON are shuffled to form six-letter word. In how many of all the possible resultant words does B come before N?

A. 120
B. 180
C. 240
D. 360
E. 720

Source :- globalexperts

ankush8998 · Answer

The word BOSTON can be arranged in 6!/2! ways.
And B,N can be arranged within themselves in 2! ways. But only one of these will have B before N.
So 6!/(2!+2!) = 180

chetan2u · Answer

Total ways to firm six letter word =6!/2!=360..
B before N...
Half of 360 will have B before N and other half N before B..
So ans =360/2=180

B

chetan2u · Answer

Logic is correct but you are wrong in coloured portion..
It will be 6!/(2!*2!) And not 6!/(2!+2!)..
Answer is still correct because 2!+2!=2!*2!

Kinshook · Answer

Given: Letters of the word BOSTON are shuffled to form six-letter word.

Asked:In how many of all the possible resultant words does B come before N?

Number of 6-letter words formed with letters of the word BOSTON = 6!/2! =360
In half of the words, B will come before N.

IMO B

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pappal · Answer

if B is at the start then N has 5 places, if at second N has 4 places ..........if at 5th place then N has just 1 place
so various places of B &N in the words=5+4+3+2+1=15 -------i
Rest places in the words can be filled in 4!/2!=12 i.e. arrangement of O S T O in 4 places------ii
so required no. of words=15*12=180 since for the formation of words both conditions should be satisfied simultaneously (AND condition)
B

Letters of the word BOSTON are shuffled to form six-letter word. In ho

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