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| Last visit was: 22 Apr 2026, 19:12 |
It is currently 22 Apr 2026, 19:12 |
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Question Stats:
94% (00:38) correct
6%
(00:49)
wrong
based on 509
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| We have two cases as we have |x + 3| | |
| -Case 1: x+3 ≥ 0 or x ≥ -3 => |x + 3| = x + 3 => x + 3 = 4 => x = 1 But the condition was x ≥ -3 and x = 1 ≥ -3 => x = 1 is a SOLUTION | -Case 2: x+3 ≤ 0 or x ≤ -3 => |x + 3| = -(x + 3) => -(x + 3) = 4 => -x - 3 = 4 => x = -3 - 4 = -7 But the condition was x ≤ -3 and x = -7 ≤ -3 => x = -7 is a SOLUTION |
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