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24 May 2018, 05:28
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D
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Difficulty:
25%
(medium)
Question Stats:
79% (01:50) correct
21%
(02:01)
wrong
based on 159
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Kelly took three days to travel from City A to City B by automobile. On the first day, Kelly traveled 2/5 of the distance from City A to City B and on the second day, she traveled 2/3 of the remaining distance. Which of the following is equivalent to the fraction of the distance from City A to City B that Kelly traveled on the third day.
A) \(1 - \frac{2}{5} - \frac{2}{3}\)
B) \(1 - \frac{2}{5} - \frac{2}{3}(\frac{2}{5})\)
C) \(1 - \frac{2}{5} - \frac{2}{5}(1 - \frac{2}{3})\)
D) \(1 - \frac{2}{5} - \frac{2}{3}(1 - \frac{2}{5})\)
E) \(1 - \frac{2}{5} - \frac{2}{3}(1 - \frac{2}{5} - \frac{2}{3})\)
A) \(1 - \frac{2}{5} - \frac{2}{3}\)
B) \(1 - \frac{2}{5} - \frac{2}{3}(\frac{2}{5})\)
C) \(1 - \frac{2}{5} - \frac{2}{5}(1 - \frac{2}{3})\)
D) \(1 - \frac{2}{5} - \frac{2}{3}(1 - \frac{2}{5})\)
E) \(1 - \frac{2}{5} - \frac{2}{3}(1 - \frac{2}{5} - \frac{2}{3})\)
24 May 2018, 19:57
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Bunuel
Let the total distance to be traveled from City A to City C be 1.
Kelly travels \(\frac{2}{5}\) of the distance on the first day.
After the first day, Kelly would have to travel \(1 - \frac{2}{5}\) of the distance
Kelly travels \(\frac{2}{3}\)rd of the remaining distance on the second day.
On the second day, Kelly would have traveled \(\frac{2}{3}(1 - \frac{2}{5})\)
Therefore, on the third day, Kelly will have to travel \(1 - \frac{2}{5} - \frac{2}{3}(1 - \frac{2}{5})\) of the distance (Option D)
29 May 2018, 16:16
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Bunuel
We are given that Kelly traveled 2/5 of the distance from City A to City B and 2/3 of the remaining distance on the second day. So she traveled 2/3(1 - 2/5) of the distance on the second day and thus on the third day, the fraction of the distance she needs to travel was:
1 - 2/5 - 2/3(1 - 2/5)
Answer: D
