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Bunuel


What is the perimeter of the rectangle shown above?

(A) 14
(B) 24
(C) 28
(D) 38
(E) 48

Attachment:
rectangle..jpg

The length, breadth(6 unit), and diagonal(10 unit) of the given rectangle form two right angled triangles.

So, length=\(\sqrt(10^2-6^2)\)=8 unit (Applying Pythagoras property in any one of the triangles)

Now, perimeter of rectangle= 2(length+breadth)=2(8+6)=2*14=28 unit

Therefore, correct answer choice is (C).
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Bunuel


What is the perimeter of the rectangle shown above?

(A) 14
(B) 24
(C) 28
(D) 38
(E) 48

Attachment:
rectangle..jpg


Use Pythagorean theorem to find base

10^2 = 6^2 + b^2
100 = 36 + b^2
64 = b^2
b = 8

Perimeter = 8+8+6+6 = 28

Ans = C
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Bunuel


What is the perimeter of the rectangle shown above?

(A) 14
(B) 24
(C) 28
(D) 38
(E) 48

Attachment:
rectangle..jpg

We see that we have a 6-8-10 right triangle, so the length of the rectangle must be 8.

Thus, the perimeter is 6 x 2 + 8 x 2 = 12 + 16 = 28.

Answer: C
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