Bunuel
The average (arithmetic mean) weight of 5 crates is 250 pounds. The 2 lightest crates weigh between 200 and 205 pounds each, inclusive, and the 2 heaviest crates weigh between 300 and 310 pounds each, inclusive. If the weight of the fifth crate is x pounds, then x is expressed by which of the following?
A) 220 ≤ x ≤ 250
B) 230 ≤ x ≤ 260
C) 240 ≤ x ≤ 270
D) 250 ≤ x ≤ 270
E) 260 ≤ x ≤ 280
\(?\,\,\,:\,\,\,x \in \left[ {{x_{\min }}\,\,,\,\,\,{x_{\max }}} \right]\)
By the
homogeneity nature of the average, we know that:
\(\sum\nolimits_5 = \,\,\,5 \cdot 250 = 1250\)
\(\sum\nolimits_{2\,{\text{light}}}^{\min } = \,\,\,2 \cdot 200 = 400\,\,\,\,\,\,;\,\,\,\,\,\,\sum\nolimits_{2\,{\text{light}}}^{\max } = \,\,\,2 \cdot 205 = 410\)
\(\sum\nolimits_{2\,{\text{heavy}}}^{\min } = \,\,\,2 \cdot 300 = 600\,\,\,\,\,\,;\,\,\,\,\,\,\sum\nolimits_{2\,{\text{heavy}}}^{\max } = \,\,\,2 \cdot 310 = 620\)
\({x_{\min }} = \sum\nolimits_5 { - \left( {\,\sum\nolimits_{2\,{\text{light}}}^{\max } { + \sum\nolimits_{2\,{\text{light}}}^{\max } {} } } \right)} = 1250 - \left( {410 + 620} \right) = 220\)
\({x_{\max }} = \sum\nolimits_5 { - \left( {\,\sum\nolimits_{2\,{\text{heavy}}}^{\min } { + \sum\nolimits_{2\,{\text{heavy}}}^{\min } {} } } \right)} = 1250 - \left( {400 + 600} \right) = 250\)
\(?\,\,\,:\,\,\,x \in \left[ {220,250} \right]\,\,\,\,\, \Leftrightarrow \,\,\,\,\,220 \leqslant x \leqslant 250\)
This solution follows the notations and rationale taught in the GMATH method.
Regards,
Fabio.