Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Apr 2301:30 AM EDT
-02:30 AM EDT
Struggling with GMAT Verbal as a non-native speaker? Harsh improved his score from 595 to 695 in just 45 days—and scored a 99 %ile in Verbal (V88)! Learn how smart strategy, clarity, and guided prep helped him gain 100 points.
Apr 2308:00 PM PDT
-09:00 PM PDT
Video explanations + diagnosis of 10 weakest areas + 150+ short videos + study plan!
Apr 2212:30 AM EDT
-01:30 AM EDT
At one point, she believed GMAT wasn’t for her. After scoring 595, self-doubt crept in and she questioned her potential. But instead of quitting, she made the right strategic changes. The result? A remarkable comeback to 695. Check out how Saakshi did it.
Apr 2610:00 AM EDT
-11:00 AM EDT
The Target Test Prep course represents a quantum leap forward in GMAT preparation, a radical reinterpretation of the way that students should study. Try before you buy with a 5-day, full-access trial of the course for FREE!
Apr 2711:00 AM EDT
-12:00 PM EDT
Prefer video-based learning? The Target Test Prep OnDemand course is a one-of-a-kind video masterclass featuring 400 hours of lecture-style teaching by Scott Woodbury-Stewart, founder of Target Test Prep and one of the most accomplished GMAT instructors
Apr 2808:00 AM PDT
-11:00 AM PDT
Whether you are just beginning your MBA journey or fine-tuning your path to a 700+ score, GMAT Day is designed to give you a competitive edge.
12 Jun 2018, 18:13
Kudos
Bookmarks
D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
15%
(low)
Question Stats:
84% (01:30) correct
16%
(01:42)
wrong
based on 90
sessions
History
Date
Time
Result
Not Attempted Yet
[GMAT math practice question]
When n is divided by 2, 3, 5, 7 and 9, the remainder is 1. What is the smallest value of the positive integer n?
A. 100
B. 211
C. 421
D. 631
E. 841
When n is divided by 2, 3, 5, 7 and 9, the remainder is 1. What is the smallest value of the positive integer n?
A. 100
B. 211
C. 421
D. 631
E. 841
DentTheUniverse
GMAT 1: 720 Q48 V41
Posts: 7
12 Jun 2018, 19:28
Kudos
Bookmarks
I employed logic to start:
A --> eliminate b/c it's even and 2 will not have a remainder. It's also a multiple of 5, so it won't have a remainder either.
Don't need to test 5 because each B, C, D, E will have a remainder of 1. Employing general number sense, we know that 21, 42, 63, 84 are divisible by 3 and so their multiple (each *10) are divisible by 3, so B, C, D, and E will each have a remainder 1 when divided by 3.
I'm not as strong with the number properties of 7, so I'm going to test 9.
Numbers are divisible by 9 when the digits add up to 9. So to have a remainder of 1, the digits need to add up to 8 or 10.
B--> eliminate. Sum of digits is 4 (2+1+1), which is not 8 or 10 so won't have a remainder of 1 when divided by 9 (remainder will be 4 - don't need to calculate while doing the problem!)
C--> eliminate. Sum of digits is 7 (4+2+1), which is not 8 or 10 so won't have remainder 1 when divided by 9 (remainder will be 7).
E--> eliminate. Sum of digits is 13 (8+4+1), not 8 or 10 so won't have remainder of 1 when divided by 9 (remainder will be 4).
That leaves D. To make sure 7 has a remainder 1, we can implore # sense. 63 is a multiple of 7, therefore 630 is (63*10) and 631 will have a remainder 1.
A --> eliminate b/c it's even and 2 will not have a remainder. It's also a multiple of 5, so it won't have a remainder either.
Don't need to test 5 because each B, C, D, E will have a remainder of 1. Employing general number sense, we know that 21, 42, 63, 84 are divisible by 3 and so their multiple (each *10) are divisible by 3, so B, C, D, and E will each have a remainder 1 when divided by 3.
I'm not as strong with the number properties of 7, so I'm going to test 9.
Numbers are divisible by 9 when the digits add up to 9. So to have a remainder of 1, the digits need to add up to 8 or 10.
B--> eliminate. Sum of digits is 4 (2+1+1), which is not 8 or 10 so won't have a remainder of 1 when divided by 9 (remainder will be 4 - don't need to calculate while doing the problem!)
C--> eliminate. Sum of digits is 7 (4+2+1), which is not 8 or 10 so won't have remainder 1 when divided by 9 (remainder will be 7).
E--> eliminate. Sum of digits is 13 (8+4+1), not 8 or 10 so won't have remainder of 1 when divided by 9 (remainder will be 4).
That leaves D. To make sure 7 has a remainder 1, we can implore # sense. 63 is a multiple of 7, therefore 630 is (63*10) and 631 will have a remainder 1.
12 Jun 2018, 19:28
Kudos
Bookmarks
we can eliminate A) because it exacts gets divided by 2 and 5
B) 211=210+1
If we divide 211 by 9 we wont get remainder 1.So option B is WRONG
C)421=420+1
421 gets divided by 9 exactly. SO C is WRONG
D)631=630+1
This satisfies the above question. If we divide 631 by 2,3,5,7,9 we get the remainder 1. So D is CORRECT
E)840=840+1
If we divide 840 by 9 it does not give the remainder 1. SO this option is Wrong
B) 211=210+1
If we divide 211 by 9 we wont get remainder 1.So option B is WRONG
C)421=420+1
421 gets divided by 9 exactly. SO C is WRONG
D)631=630+1
This satisfies the above question. If we divide 631 by 2,3,5,7,9 we get the remainder 1. So D is CORRECT
E)840=840+1
If we divide 840 by 9 it does not give the remainder 1. SO this option is Wrong
