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Bunuel
The numbers a, b, and C are chosen at random, with replacement, from the set of integers from 1 to 20, inclusive. What is the probability that ab − c is odd?

A. 1/8
B. 1/4
C. 3/8
D. 1/2
E. 3/4

Solution


    • From 1 to 20 there are 20 integers in which 10 are odd and 10 are even.
      o The probability of picking an even number P(E) = The probability of picking an odd number P(O) \(= \frac{1}{2}\)
    • The following table shows the cases when ab – c will be odd and the probability of the corresponding cases:

    • Thus, P(ab – c is odd) \(= 4*\frac{1}{2}*\frac{1}{2} *\frac{1}{2} = \frac{4}{8} = \frac{1}{2} \)
Thus, the correct answer is Option D.
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Bunuel
The numbers a, b, and C are chosen at random, with replacement, from the set of integers from 1 to 20, inclusive. What is the probability that ab − c is odd?

A. 1/8
B. 1/4
C. 3/8
D. 1/2
E. 3/4

Given:The numbers a, b, and C are chosen at random, with replacement, from the set of integers from 1 to 20, inclusive.
Asked: What is the probability that ab − c is odd?



abcab-c
EVENEVENEVENEVEN
EVENEVENODDODD
EVENODDEVENEVEN
EVENODDODDODD
ODDEVENEVENEVEN
ODDEVENODDODD
ODDODDEVENODD
ODDODDODDEVEN

Probability that ab-c is odd =\( \frac{4}{8} = \frac{1}{2}\)

IMO D
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Solution


Given

    • There is a set with integers from 1 to 20.
    • A, B, C are three numbers picked up randomly with replacement.

To Find
    • the probability that AB – C is odd.

Approach and Working Out

We need not find the number of cases here.

A logical way is to understand that we are not biased towards odd or even (as we have 10 each) and thus AB – C is equally likely to become an odd number or an even number.

Let’s see what I mean by that.

    • At any moment there are 10 odd numbers and 10 even numbers as we are replacing the picked-up numbers.
      o AB – C can be odd if,
         AB is even and C is odd or
         AB is odd and C is even.
    • Once we have picked up A and B,
      o We already know the odd-even nature of AB.
      o If AB is odd, then we should pick an even number for C.
         The probability is ½.
      o If AB is even, then we should pick an odd number for C.
         Again, the probability is ½.

Correct Answer: Option D
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This could be an alternative approach.

There is an equal number of even and odd possible number and everyone has equal chance.

Given ab-c = odd
Then ab and c opposite parity
1)
ab even => 3/4 chance (ee, oe, eo)
c odd => 1/2
2)
Ab odd => 1/4(oo)
C even => 1/2


3/8 + 1/8 = 1/2
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The numbers a, b, and C are chosen at random, with replacement, from the set of integers from 1 to 20, inclusive. What is the probability that ab − c is odd?

There are 4 ways in which ab - c can be odd.

odd × odd - even

even × even - odd

even × odd - odd

odd × even - odd

Since the numbers a, b, and c are chosen at random with replacement from a set of integers, 1 to 20, such that half are even and half are odd, for each of those numbers chosen, the probability that that number will be even is 1/2, and the probability that that number will be odd is 1/2.

So, the probability of each of the above 4 favorable outcomes is 1/2 × 1/2 × 1/2 = 1/8.

4 × 1/8 = 1/2

A. 1/8
B. 1/4
C. 3/8
D. 1/2
E. 3/4


Correct answer: D
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