Bunuel
The number of years it would take for the value of an investment to double, at 26% interest compounded annually, is approximately which of the following?
(A) 2
(B) 3
(C) 4
(D) 5
(E) 6
Agreed, estimation is the way to go. A compound interest rate of 26% translates into a multiplier of 1.26. Change to 1.25
\(1.25=1\frac{25}{100}=1\frac{1}{4}=\frac{5}{4}\)
Imagine 1 in an account.
Multiply \(1*\frac{5}{4}*\frac{5}{4}*\frac{5}{4}\) ... until the numerator is about twice the denominator.
Each time the multiplier
gets used = 1 year has elapsed
(the multiplier is being used at the
end of each year, with a first year base of 1)
\(1*\frac{5}{4}*\frac{5}{4}*\frac{5}{4}=\frac{125}{64}\) => 125 is \(\approx\) double 64
Number of years? \(\frac{5}{4}\) was used three times, i.e., at the end of each of 3 years
Answer BSame as above with $1 and years shown
Begin: \($1=>\)End Year 1: \(($1*\frac{5}{4})=$\frac{5}{4}\)
Begin: \($\frac{5}{4}=>\)END Year 2: (\($\frac{5}{4}*\frac{5}{4})=$\frac{25}{16}\)
Begin: \($\frac{25}{16}=>\)END Year 3: \(($\frac{25}{16}*\frac{5}{4})=$\frac{125}{64}\)
\($125\) is just about double \($64\)
One more year? Check
Begin:
\($\frac{125}{64}=>\)END Year 4:\(($\frac{125}{64}*\frac{5}{4})=$\frac{625}{256}\)MORE than doubled. (256*2 = 512). Too many years.
End of Year 3 was correct.
Answer B