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Bunuel
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The integers k, l, and m are consecutive even integers between 23 and 14 Aug 2018, 02:12
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The integers k, l, and m are consecutive even integers between 23 and 33. Which of the following could be the average (arithmetic mean) of k, l, and m?

(A) 24
(B) 25
(C) 25.5
(D) 28
(E) 32
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D
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The integers k, l, and m are consecutive even integers between 23 and 14 Aug 2018, 02:30
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Bunuel
The integers k, l, and m are consecutive even integers between 23 and 33. Which of the following could be the average (arithmetic mean) of k, l, and m?

(A) 24
(B) 25
(C) 25.5
(D) 28
(E) 32
Show more


Probable values of k l m : 24 -26 -28 - 30 - 32. As they are consecutive even integers:

1) 24-26-28

2) 26-28-30

3) 28-30-32


So 28 could be the average.

The best answer is D.
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The integers k, l, and m are consecutive even integers between 23 and 14 Aug 2018, 02:44
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Bunuel
The integers k, l, and m are consecutive even integers between 23 and 33. Which of the following could be the average (arithmetic mean) of k, l, and m?

(A) 24
(B) 25
(C) 25.5
(D) 28
(E) 32
Show more

These 3 can be written as
k,K+2,k+4 = 3k+6
am = (3k+6)/3 = k+2

following are possible

1.24,26,28
2.26,28,30
3.28,30,32

From answer choices we can confirm that am = 28
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The integers k, l, and m are consecutive even integers between 23 and 14 Aug 2018, 04:02
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Bunuel
The integers k, l, and m are consecutive even integers between 23 and 33. Which of the following could be the average (arithmetic mean) of k, l, and m?

(A) 24
(B) 25
(C) 25.5
(D) 28
(E) 32
Show more

Between 23 and 33, consecutive even integers are 24,26,28,30,32
So, 3 consecutive integers may be paired as
1. 24,26,28
2. 26,28,30
3. 28,30,32

The middle number will be the average of 3 consecutive integers. So, the average could be 26 or 28 or 30

Hence, Answer D
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The integers k, l, and m are consecutive even integers between 23 and 21 Aug 2018, 23:07
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The question says there are 3 consecutive even integers and we need find average of them. Even numbers between 23 and 33 will be {24, 26, 28, 30, 32}.
We know that the average of three consecutive terms has to be the middle term. That means for the question it has to be the even term. So we can eliminate option (B) and (C). Now, it can also be seen that 24 and 32 cannot be mean, as they are not the middle values of the set above. So, the correct answer option is (D).
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The integers k, l, and m are consecutive even integers between 23 and 26 Jan 2024, 21:52
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Bunuel
The integers k, l, and m are consecutive even integers between 23 and 33. Which of the following could be the average (arithmetic mean) of k, l, and m?

(A) 24
(B) 25
(C) 25.5
(D) 28
(E) 32
Show more
Sum of 3 Even Integers must be Even ...

Then again, Even/Odd = Even (For average)

Thus, among the given options we may reject options (B) and (C)

Min Possible value of k ,l & m = 24 , 26 & 28, Here Avg = (24+26+28/3 = 26)
Max Possible value of k ,l & m = 28 , 30 & 32, Here Avg = (28+30+32/3 = 30)

Thus the range of value must be between 26 to 30....... (Options (A), (B) & (E) can be rejected), Answer mst be (D)...

Check the option (D)...

If, \(k = 26\), \(l = 28\) & \(m = 30\) then \(k + l + m = 84\), Avg of \(k , l\) & \(m = 28\)
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The integers k, l, and m are consecutive even integers between 23 and 06 Jan 2025, 03:34
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Given k, l, m are evenly spaced, the avg is going to be the middle term, which is even. That eliminates B (odd), C(not an integer).
24 and 32 are extremes (cannot have a term lower than 23 or higher than 33), cannot be the middle term, so eliminate A, E
Answer is D
Bunuel
The integers k, l, and m are consecutive even integers between 23 and 33. Which of the following could be the average (arithmetic mean) of k, l, and m?

(A) 24
(B) 25
(C) 25.5
(D) 28
(E) 32
Show more
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