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Solution


To find:
    • The option which has a value less than 1

Approach and Working:
    • If the Numerator < Denominator, then \(\frac{N}{D} < 1\) (Note D must be > 0)
    • Option A: N = 14, D = 13, implies, N > D
    • Option B: N = \(\sqrt{10} > 3\), D = 2, implies, N > D
    • Option C: N = 2, D = \(\sqrt{2}\), implies, N > D
    • Option D: \(N = 1, D = \frac{1}{2}\), implies, N > D
    • Option E: \(N = 9^2 = 81\), \(D = 10^2 = 100\), implies, N < D

Thus, the value of \((\frac{9}{10})^2\) is less than 1

Hence, the correct answer is option E

Answer: E

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Bunuel
Which of the following has a value less than 1?


A. \(2(\frac{7}{13})\)

B. \(\frac{\sqrt{10}}{2}\)

C. \(\frac{2}{\sqrt{2}}\)

D. \(\frac{1}{\frac{1}{2}}\)

E. \((\frac{9}{10})^2\)

Which of the following has a value less than 1?


A. \(2(\frac{7}{13}) = 14/13 >1\)

B. \(\frac{\sqrt{10}}{2} = 3.2/2 = 1.6>1\)

C. \(\frac{2}{\sqrt{2}} = 2/1.4 >1\)

D. \(\frac{1}{\frac{1}{2}} = 2>1\)

E. \((\frac{9}{10})^2 = 81/100 < 1\)

IMO E
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Bunuel
Which of the following has a value less than 1?


A. \(2(\frac{7}{13})\)

B. \(\frac{\sqrt{10}}{2}\)

C. \(\frac{2}{\sqrt{2}}\)

D. \(\frac{1}{\frac{1}{2}}\)

E. \((\frac{9}{10})^2\)





Nick Slavkovich, GMAT/GRE tutor with 20+ years of experience

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