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Bunuel
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Bunuel
At a church prayer, (3/5)th of the members were males and (3/5)th of the male members attended the prayer. If (7/10)th of the female members attended the prayer, what fraction of the members at the prayer who did not attend the prayer are males?

(A) 1/4

(B) 3/7

(C) 2/3

(D) 9/10

(E) 6/19
Attachment:
prayermatrix.jpg
This language is misleading. We have:
A church prayer and THE prayer
The first is a large category. The second is a small category and a subset of the first.
The categories are not similar. Time to rewrite:

Men and women are members of and in a CHURCH (= "A church prayer")
Some men and women ATTEND a PRAYER in a separate room (= "THE prayer")
We are interested in the group who goes to the separate room.

A double matrix is quick. Assign values.
The numbers in the matrix in the diagram were entered in the sequence below.

Use LCM of 5 and 10. Let total church members = 50

• Number of male vs. number of female CHURCH members (who may or may not attend a prayer)

Male, \(\frac{3}{5}\) of all members: \(\frac{3}{5}*50\) = 30

Female, must be \(\frac{2}{5}\) of all: \(\frac{2}{5}*50\) = 20

• Number of men and women in the church who DID and DID NOT attend a prayer

Females: \(\frac{7}{10}\) of all female members (20) DID attend a prayer: \((\frac{7}{10}*20)=14\)
Females who DID attend: 14

Females who DID NOT attend: (20 - 14) = 6

Males: \(\frac{3}{5}\) of all male members (30) attended a prayer: \((\frac{3}{5}*30)=18\)
Males who DID attend =18

Males who DID NOT attend: (30 - 18) = 12

• TOTALS - who DID and DID NOT attend a prayer

Total WHO DID attend a prayer = (18 + 14) = 32

Total who DID NOT attend a prayer: (50 - 32) = 18

• What fraction of the members at the prayer CHURCH, who did not attend the A prayer, are males?
Total who DID NOT attend: 18
Number of that group who were male: 12
Fraction = \(\frac{12}{18}=\frac{2}{3}\)

Answer C




Why did you take the total as 50?
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You can take any number. 50 or 100 etc. What makers is the LCM of the denominators. Find the common number that will be easily divisible by the denominators. Tat makes calculation easy and quick. Or else go with the d approach.
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