Bunuel
In a conference of 3 delegates from each of 8 different organizations, each delegate shook hands with every person other than those from his or her own organization. How many handshakes took place in the conference?
(A) 48
(B) 96
(C) 252
(D) 270
(E) 504
This is a tricky one.
1,1,1
2,2,2
3,3,3 etc..
If the delegates from group (1) shake hands with each from group (2) this means 3 hand shakes for each of the delegates from Group 1.
Since delegates from group (1) will shake hands with all delegates from 2,3,4,5,6,7,8
It means each member in group 1 will shake hands 21 times. (8-1)*3 = 21
8-1 = 7 to exclude the hand shakes from their group.
Since each shakes hand once it means per group they have 21*3 = 63
There are 8 groups so it means 63*8 = 504
But this double-counts.
So we divide it by 2 we get 504/2 = 252.
Answer choice C.
Another way would be to say
A member of group one gets 21 hand shakes
A member of group two gets 18
A member of group three gets 15
A member of group four gets 12
A member of group five gets 9
A member of group six gets 6
A member of group seven gets 3
And a member of group 8 gets 0.
Adding all the above numbers we get 84
And 84*3 = 252
Here the 3 is to account for 3 members in the group.
I hope it is clear
Posted from my mobile device