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1 company = 3 delegates
Total companies present = 8
Total number of delegates = 24

In the question, each delegate shook hands with every person other than those from his or her own organization
=>1 delegate will shake hands with 21 other delegates
=>Total = 21 handshakes

There are a total of 24 delegates and therefore the total number of handshakes = 21x24 = 504 Handshakes(This includes the repetition of handshakes)
So we should divide it by 2
=>504/2
=>252

Hence C is the answer
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Bunuel
In a conference of 3 delegates from each of 8 different organizations, each delegate shook hands with every person other than those from his or her own organization. How many handshakes took place in the conference?

(A) 48
(B) 96
(C) 252
(D) 270
(E) 504

Consider the 3 delegates of the first org. Each of the 3 delegates will shake hands with delegates from the other 7 organisations i.e. with 7*3 people.
Consider the next team of delegates from the second org. Each of the 3 delegates will shake hands with delegates of other 6 orgs (since they have already shaken hands with the first org delegates) i.e. with 6*3 = 18 people.
So we see the pattern: No of handshakes = 3*(21 + 18 + ... + 3)

The underlined is an AP. Its sum = (No of terms)*(First term + last term)/2

Sum = 3 * 7*(21 + 3)/2 = 3*84 = 252

Answer (C)
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­KarishmaB Bunuel is the below approach correct?­
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­KarishmaB Bunuel is the below approach correct?­
­That's correct too.
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Light11
­KarishmaB Bunuel is the below approach correct?­
­That's correct too.
­Thankyou KarishmaB !!
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If we had to count the handshakes with the delegation that the person belonged to, then we would have 8 * 3 = 24 ( for the number of handshakes)
then, we would take the number of people shaking their hands = 8 *3 again, as 24 people

so 24 * 24 / 2 (as to exclude the double counting) = 288


Can anyone confirm this? (note: I have excluded the part of each delegate shook hands with every person other than those from his or her own organization, just to try this way out)
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riri3026
In a conference of 3 delegates from each of 8 different organizations, each delegate shook hands with every person other than those from his or her own organization. How many handshakes took place in the conference?

(A) 48
(B) 96
(C) 252
(D) 270
(E) 504

If we had to count the handshakes with the delegation that the person belonged to, then we would have 8 * 3 = 24 ( for the number of handshakes)
then, we would take the number of people shaking their hands = 8 *3 again, as 24 people

so 24 * 24 / 2 (as to exclude the double counting) = 288


Can anyone confirm this? (note: I have excluded the part of each delegate shook hands with every person other than those from his or her own organization, just to try this way out)
­
Total - Restriction approach would be:

24C2 - 8*3 = 276 - 24 = 252.
Answer: C.­
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­hi!
i'd like someone to take a look to my answer.

there are 8 groups of 3, meaning that each group will interact with another group in 8C2 = 28
we have 28 ways to create couples of groups from 8 groups. each couple of groups will "generate" C(6,2) - 2*C(3,2) = 9 (or put more simply 3^2) handshakes.
in total we have 28 * 9 handshakes = 252­
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pierjoejoe
­hi!
i'd like someone to take a look to my answer.

there are 8 groups of 3, meaning that each group will interact with another group in 8C2 = 28
we have 28 ways to create couples of groups from 8 groups. each couple of groups will "generate" 3^2 = 9 handshakes.
in total we have 28 * 9 handshakes = 252­
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­That's correct.
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