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Difficulty:
15%
(low)
Question Stats:
87% (02:08) correct
13%
(02:26)
wrong
based on 172
sessions
History
Date
Time
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Not Attempted Yet
Two cyclists, A and B, are 145 miles apart on a straight road. At 1:30 p.m., cyclist A begins riding at a constant speed of 20 miles per hour toward cyclist B. At 2:00 p.m., cyclist B begins riding toward cyclist A at a constant speed. At 5:00 p.m. they meet. How fast, in miles per hour, was cyclist B riding?
A. 20
B. 25
C. 30
D. 35
E. 40
A. 20
B. 25
C. 30
D. 35
E. 40
Bunuel
From 1:30 to 2:00, only cyclist A rides at 20 mph toward B. A covers a distance of 10 miles in half an hour so at 2:00, distance between them is 135 miles.
This distance of 135 miles is covered by both of them together in 3 hrs.
Total Relative Speed = Speed of A + Speed of B = Distance/Time = 135/3 = 45 mph.
Speed of A = 20 mph so speed of B must be 45 - 20 = 25 mph
Answer (B)
