Let \(d\) be the distance between Rachel and Rob, which is initially \(190\) miles.
Rachel drives at a speed of \(50\) mph and Rob drives at a speed of \(70\) mph.
Since they are driving towards each other, their relative speed is the sum of their speeds:
\(50 + 70 = 120\) mph.
Let \(t\) be the time in hours until they meet. Then,
\(120t = 190\)
\(t = \frac{190}{120} = \frac{19}{12}\) hours.
We want to find the distance between them 45 minutes before they meet.
45 minutes is \(\frac{45}{60} = \frac{3}{4}\) hours.
So we want to find the distance between them at time
\(t - \frac{3}{4} = \frac{19}{12} - \frac{3}{4} = \frac{19}{12} - \frac{9}{12} = \frac{10}{12} = \frac{5}{6}\) hours.
In \(\frac{5}{6}\) hours, Rachel travels
\(50 \cdot \frac{5}{6} = \frac{250}{6} = \frac{125}{3}\) miles.
In \(\frac{5}{6}\) hours, Rob travels
\(70 \cdot \frac{5}{6} = \frac{350}{6} = \frac{175}{3}\) miles.
The total distance they have traveled is
\(\frac{125}{3} + \frac{175}{3} = \frac{300}{3} = 100\) miles.
Therefore, the distance between them at that time is
\(190 - 100 = 90\) miles.
Final Answer: The final answer is \(\boxed{90}\)