If x is an integer, then which of the following statements about x^2 – x – 1 is true?
A) It is always odd.
B) It is always even.
C) It is always positive.
D) It is even when x is even and odd when x is odd.
E) It is even when x is odd and odd when x is even.
Solution:A) If x is an Odd#, then x^2 is O#*O# so also O#, then - O# we get an Even#, then -1 (O#) answer becomes an O#
x=3, 9-3-1 = 5
B) If x is an Even#, then x^2 is E#, E#-E# = E#, then -1 (O#) we get an O# again.
x=2, 4-2-1 = 1
So there's no way that the result can be even. B is out.
C) When there's exponents and fractions together this issue always comes up.
x=1/2, 1/4 - 1/2 - 1 = -5/4 so not necessarily positive
Same with x=-1/2, 1/4 + 1/2 - 1 = -1/4
D) and E) restate A) and B) but are only half correct, can check using the same examples
Official explanation:
Because x is an integer, x must be either even or odd. If x is even, then x^2 – x must also be even, and therefore x^2 – x – 1 is always odd. If x is odd, then x^2 – x must be even, and again, x^2 – x – 1 is always odd. You can also solve this problem by Plugging In. After Plugging In several values for x and calculating x^2 – x – 1, you will discover that the result is always odd. The correct answer is (A).