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Ish1996
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Bunuel
Terrence has 2/3 as many cards as Phillip. If Terrence were to win one card from Phillip, he would have 3/4 as many cards as Phillip. If Terrence wins an even number of cards from Phillip, which of the following could be the number of cards that Phillip has left?


I. 19
II. 18
III. 17

A. I only
B. II only
C. III only
D. I and II only
E. I and III only

in best case scenario
Philip can have 21 cards in total ;
which sufficies all given relation
so if even cards are taken out ; Philip will have 19 cards or 17 cards left
IMO E
as odd-even = odd integer options would be correct..

Hey, can you please go into detail on your answer?

Ish1996
Well I actually solved the question using answer options as hint..
so seeing 19,18,17 ; the best pick of the cards which Philip can have is 21
case 1: Terrence has 2/3 as many cards as Phillip; Terrence has ; 14 cards
now question says "If Terrence were to win one card from Phillip, he would have 3/4 as many cards as Phillip"
so
since P= 21 ; taking 1 card would make it 20 ; and adding 1 to T will make him have 15 cards ; or say T = 20*3/4 = 15

secondly : "If Terrence wins an even number of cards from Phillip, which of the following could be the number of cards that Phillip has left"

knowing the rule that odd integer-even integer ; odd integer ; we can say from given option that Philips would end with an odd integer count of cards upon giving even cards..
so option 19,17 are correct...

hope this helps..
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Statement tells us:
>Philip has x cards
>Terrence has 2x/3 cards

ratio:

P/T = x / (2x/3)

hint from statement:

P-1/T+1 = x / 3x/4

(substitute P and T by our initial values)--> x-1/(2x/3 + 1) = x/(3x/4) ---> if we solve for x, we get: x=21

so Philip has 21 cards initially, which means that Terrence has 2/3*(21)=14 cards.

(now play with the answer options) --> if we remove an even number from poor Philip, e.g. 2, he's left with 21-2=19 (answer choice I). Also, removing 4, he'd be left with 21-4=17 (answer choice III).
Thus, IMO E
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