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Bunuel
At least 15 percent of the students registered for Professor Tyler’s course dropped out before the end of the course. The drop-out rate for Professor Quin’s course was 20 percent greater than that for Professor Tyler’s course. If 120 students remained on the last day of Professor Quin’s class, which of the following could be the number of students who signed up for Professor Quin’s class?

I. 147
II. 162
III. 185

A. I only
B. I and II only
C. II and III only
D. I and III only
E. I, II, and III

If the drop out rate of prof. Tayler class is at least 15% and drop out rate of prof. Quin class is 20% greater, it means that the drop out rate of Prof. Quin class ;
(1+0.2)*0.15 = 0.18.

There are 120 student at the end of the course, this means that 120 = X - 0.18X, where X is the total number of students at the beginning.
It is easy to find that the minimal starting number of students is ~146 .
Thus all the choice reporting a number greater than 146 are correct
IMO E

Hi Archit3110
Did you drive equation as 20% of dropout rate of taylor’s class + dropout rate of taylor’s Class?
I can’t seem to get my head around it. ?

Thanks
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Doer01
Archit3110
Bunuel
At least 15 percent of the students registered for Professor Tyler’s course dropped out before the end of the course. The drop-out rate for Professor Quin’s course was 20 percent greater than that for Professor Tyler’s course. If 120 students remained on the last day of Professor Quin’s class, which of the following could be the number of students who signed up for Professor Quin’s class?

I. 147
II. 162
III. 185

A. I only
B. I and II only
C. II and III only
D. I and III only
E. I, II, and III

If the drop out rate of prof. Tayler class is at least 15% and drop out rate of prof. Quin class is 20% greater, it means that the drop out rate of Prof. Quin class ;
(1+0.2)*0.15 = 0.18.

There are 120 student at the end of the course, this means that 120 = X - 0.18X, where X is the total number of students at the beginning.
It is easy to find that the minimal starting number of students is ~146 .
Thus all the choice reporting a number greater than 146 are correct
IMO E

Hi Archit3110
Did you drive equation as 20% of dropout rate of taylor’s class + dropout rate of taylor’s Class?
I can’t seem to get my head around it. ?

Thanks

Doer01
I have actually first determined the value of total drop rate of Quin class
given drop out rate of prof. Tayler class is at least 15% and drop out rate of prof. Quin class is 20% greater, it means that the drop out rate of Prof. Quin class ;
(1+0.2)*0.15 = 0.18
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Bunuel
At least 15 percent of the students registered for Professor Tyler’s course dropped out before the end of the course. The drop-out rate for Professor Quin’s course was 20 percent greater than that for Professor Tyler’s course. If 120 students remained on the last day of Professor Quin’s class, which of the following could be the number of students who signed up for Professor Quin’s class?

I. 147
II. 162
III. 185

A. I only
B. I and II only
C. II and III only
D. I and III only
E. I, II, and III

Hi Bunuel,
Does "than that" in the question statement mean 20% of 15(just number) or 20% of 15%?

Thanks.
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It means 1.2 times of 15% which is 18%
Doer01


Hi Bunuel,
Does "than that" in the question statement mean 20% of 15(just number) or 20% of 15%?

Thanks.
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At least 15 percent of the students registered for Professor Tyler’s course dropped out before the end of the course. The drop-out rate for Professor Quin’s course was 20 percent greater than that for Professor Tyler’s course. If 120 students remained on the last day of Professor Quin’s class, which of the following could be the number of students who signed up for Professor Quin’s class?

Let the drop out rate of Professor Tyler's course be x%; x>= 15
The drop-out rate for Professor Quin’s course = y% = 1.2x%; y=1.2x>= 18

Let T be the total number of students who signed up for Professor Quin's class.
The students remaining on the last day of Professor Quin's class = 120 = T(1-y/100); where y>=18

y = 100(1 - 120/T) = 100 - 12000/T >=18
12000/T <= 82
T >= 12000/82 = 146.32
Since T is an integer; T>146 or T>=147

I. 147
II. 162
III. 185

A. I only
B. I and II only
C. II and III only
D. I and III only
E. I, II, and III

IMO E
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