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24 Mar 2019, 23:00
Kudos
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D
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Difficulty:
35%
(medium)
Question Stats:
71% (01:46) correct
29%
(01:51)
wrong
based on 217
sessions
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Not Attempted Yet
One fair die has faces 1, 1, 2, 2, 3, 3 and another has faces 4, 4, 5, 5, 6, 6. The dice are rolled and the numbers on the top faces are added. What is the probability that the sum will be odd?
(A) 1/3
(B) 4/9
(C) 1/2
(D) 5/9
(E) 2/3
(A) 1/3
(B) 4/9
(C) 1/2
(D) 5/9
(E) 2/3
24 Mar 2019, 23:17
Kudos
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Even+odd=odd
Probability, 1st die is odd and 2nd die is even = (2/3)*(2/3) = 4/9
probability 1st die is even and 2nd die is odd = (1/3)*(1/3) = 1/9
Thus, probability that sum is odd = 4/9 + 1/9 = 5/9
Posted from my mobile device
Probability, 1st die is odd and 2nd die is even = (2/3)*(2/3) = 4/9
probability 1st die is even and 2nd die is odd = (1/3)*(1/3) = 1/9
Thus, probability that sum is odd = 4/9 + 1/9 = 5/9
Posted from my mobile device
25 Mar 2019, 00:51
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Bunuel
odd sum = even + odd integer
so
case 1 : die 1 even integer and die 2 odd integer = 2/6 * 2/6; 1/9
case 2 ; die 1 odd integer and die 2 even integer = 4/6 *4/6 ; 4/9
sum 1/9 + 4/9 ; 5/9
IMO D
