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27 Mar 2019, 00:20
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
45%
(medium)
Question Stats:
64% (01:56) correct
36%
(01:56)
wrong
based on 169
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Doug can paint a room in 5 hours. Dave can paint the same room in 7 hours. Doug and Dave paint the room together and take a one-hour break for lunch. Let t be the total time, in hours, required for them to complete the job working together, including lunch. Which of the following equations is satisfied by t?
(A) \((\frac{1}{5} + \frac{1}{7})(t + 1) = 1\)
(B) \((\frac{1}{5} + \frac{1}{7})t + 1 = 1\)
(C) \((\frac{1}{5} + \frac{1}{7})t = 1\)
(D) \((\frac{1}{5} + \frac{1}{7})(t - 1) = 1\)
(E) \((5 + 7)t = 1\)
(A) \((\frac{1}{5} + \frac{1}{7})(t + 1) = 1\)
(B) \((\frac{1}{5} + \frac{1}{7})t + 1 = 1\)
(C) \((\frac{1}{5} + \frac{1}{7})t = 1\)
(D) \((\frac{1}{5} + \frac{1}{7})(t - 1) = 1\)
(E) \((5 + 7)t = 1\)
Archit3110
Major Poster
Updated on: 27 Mar 2019, 01:45
Originally posted by Archit3110 on 27 Mar 2019, 01:27.
Last edited by Archit3110 on 27 Mar 2019, 01:45, edited 1 time in total.
Last edited by Archit3110 on 27 Mar 2019, 01:45, edited 1 time in total.
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Bunuel
rate of D = 1/5 and D= 1/7
together rate ; 1/5+1/7
time = t-1 ; as it includes lunch break
work = 1
so 1= (1/5+1/7)* (t-1)
\((\frac{1}{5} + \frac{1}{7})(t - 1) = 1\)
IMO D
27 Mar 2019, 01:42
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Rate of doing work of dave=1/7
Rate of doing work of Doug=1/5
Total time taken including lunch to complete work =t
Total time taken excluding lunch to complete work=t-1
Therefore,1/7+1/5=1/(t-1)
(1/7+1/5)(t-1)=1
Posted from my mobile device
Rate of doing work of Doug=1/5
Total time taken including lunch to complete work =t
Total time taken excluding lunch to complete work=t-1
Therefore,1/7+1/5=1/(t-1)
(1/7+1/5)(t-1)=1
Posted from my mobile device
