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26 Apr 2019, 06:38
Kudos
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D
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Difficulty:
15%
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Question Stats:
80% (01:19) correct
20%
(01:26)
wrong
based on 1711
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The figure above is constructed by separating a circular region into 6 equal parts and rearranging the parts as shown. If the diameter of the circle is d, what is the perimeter of the figure above?
A. \(\pi d\)
B. \(2\pi d\)
C. \(\pi d + 2\)
D. \(\pi d + d\)
E. \(2\pi d + d\)
PS44602.01
Quantitative Review 2020 NEW QUESTION
Attachment:
2019-04-26_1735.png [ 26.95 KiB | Viewed 26658 times ]
26 Apr 2019, 10:42
Kudos
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Bunuel
Let's examine one sector.
If the diameter = d, then the radius = d/2
Also notice that each curved arc is 1/6 the circumference of the original circle
So, each part of the perimeter is as follows:
Perimeter = d/2 + d/2 + (1/6 of circumference) + (1/6 of circumference) + (1/6 of circumference) + (1/6 of circumference) + (1/6 of circumference) + (1/6 of circumference)
= d + circumference of circle
circumference of circle = (π)(diameter)
So, circumference of original circle = πd
So, perimeter = d + πd
Answer: D
Cheers,
Brent
General Discussion
26 Apr 2019, 08:55
Kudos
Bookmarks
IMO D
circle is divided into 6 equal parts
so angle at center = 60
so length of arc = 2*pie*(d/2)*(60/360)
= pie*d/6
so the total perimeter = 6*pie*d/6 + d
d is the sum.of two staright side
award kudo if helpful
Posted from my mobile device
circle is divided into 6 equal parts
so angle at center = 60
so length of arc = 2*pie*(d/2)*(60/360)
= pie*d/6
so the total perimeter = 6*pie*d/6 + d
d is the sum.of two staright side
award kudo if helpful
Posted from my mobile device
