Using the Concept of drawing Right Triangles to use the Pythagoras Theorem to determine Distance/Length of a Slanted Line:
If we drew a Horizontal Line on the X-Axis from Origin (0 , 0) to the Point on the X-Axis that is Vertically Beneath Point S, we would create a Horizontal Leg of a Right Triangle. Since the Hypotenuse in this Right Triangle would = Line SO, which has a Length of 6, the Length of this Horizontal Leg would have to be LESS THAN< 6 Units.
Thus, the Distance ALONG the X-Axis from Origin (0 , 0) to the Point Directly, Vertically Beneath Point S must be LESS THAN< 6 Units.
The X Coordinate of S must therefore be Greater than -6 because the X Coordinate of Point S must be to the RIGHT of (-6 , 0) on the X-Axis.
I must be true.
The Line formed by the equation y = -x has a Slope = -1. One of the features of Line y= -x is that it creates a 45 degree Angle with the origin and the X-Axis when it Intersects through the Origin.
Starting from Slope =-1 of Line y= -x ---
as Lines with (-)Negative Slopes INCREASE IN VALUE and Approach 0, they will Approach the Horizontal Line with Slope = 0. The Lines will keep "Tilting Upwards" approaching the Horizontal Line with Slope = 0.
Therefore, since the Angle formed with the X-Axis by Line SO is 40 degrees and LESS THAN the 45 Degree Angle that Line y= -x forms with the X-Axis, Line Segment SO must be starting to "Tilt Upwards" and approach Slope = 0 as described above.
Therefore, because of this Fact, the Slope must be approaching 0 and be GREATER THAN > -1
II must be True
Lastly, III must be True. Point S is in Quadrant II in which all the Y Coordinates have (+)Positive Values
I, II, and III ALL must be true
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