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Bunuel
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Bunuel
If a and b are distinct positive integers, and a is even, then which of the following must also be even?

A. 2(a + b) – 3
B. (a – b) + 2
C. a + b – 1
D. a – b
E. ab – 2

a=e and b= e/o


A. 2(a + b) – 3 ; always odd
B. (a – b) + 2; can be both o/e
C. a + b – 1; can be both o/e
D. a – b; can be both o/e
E. ab – 2;; always even
IMO E
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Bunuel
If a and b are distinct positive integers, and a is even, then which of the following must also be even?

A. 2(a + b) – 3
B. (a – b) + 2
C. a + b – 1
D. a – b
E. ab – 2


IMO E. let a =2k b= 2k+1 .

ab -2 = 2k(2k+1) - 2 = 2(k(2k+1)-1))) always even
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If a=2 and b=1 then E will be zero! (0 is neither odd nor even)
Why is everyone saying e is the right option??
I think it should be C. Please correct me if i'm wrong?
Bunuel
If a and b are distinct positive integers, and a is even, then which of the following must also be even?

A. 2(a + b) – 3
B. (a – b) + 2
C. a + b – 1
D. a – b
E. ab – 2
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if a=2 b=1 then ab-2 should be zero. Am i missing something?
Archit3110
Bunuel
If a and b are distinct positive integers, and a is even, then which of the following must also be even?

A. 2(a + b) – 3
B. (a – b) + 2
C. a + b – 1
D. a – b
E. ab – 2

a=e and b= e/o


A. 2(a + b) – 3 ; always odd
B. (a – b) + 2; can be both o/e
C. a + b – 1; can be both o/e
D. a – b; can be both o/e
E. ab – 2;; always even
IMO E
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Bunuel
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DrDilipkumar
if a=2 b=1 then ab-2 should be zero. Am i missing something?
Archit3110
Bunuel
If a and b are distinct positive integers, and a is even, then which of the following must also be even?

A. 2(a + b) – 3
B. (a – b) + 2
C. a + b – 1
D. a – b
E. ab – 2

a=e and b= e/o


A. 2(a + b) – 3 ; always odd
B. (a – b) + 2; can be both o/e
C. a + b – 1; can be both o/e
D. a – b; can be both o/e
E. ab – 2;; always even
IMO E
0 is an even integer.



ZERO:

1. Zero is an INTEGER.

2. Zero is an EVEN integer.

3. Zero is neither positive nor negative (the only one of this kind)

4. Zero is divisible by EVERY integer except 0 itself (\(\frac{0}{x} = 0\), so 0 is a divisible by every number, x).

5. Zero is a multiple of EVERY integer (\(x*0 = 0\), so 0 is a multiple of any number, x)

6. Zero is NOT a prime number (neither is 1 by the way; the smallest prime number is 2).

7. Division by zero is NOT allowed: anything/0 is undefined.

8. Any non-zero number to the power of 0 equals 1 (\(x^0 = 1\))

9. \(0^0\) case is NOT tested on the GMAT.

10. If the exponent n is positive (n > 0), \(0^n = 0\).

11. If the exponent n is negative (n < 0), \(0^n\) is undefined, because \(0^{negative}=0^n=\frac{1}{0^{(-n)}} = \frac{1}{0}\), which is undefined. You CANNOT take 0 to the negative power.

12. \(0! = 1! = 1\).
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