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energetics
If x < 10, y < 8, and x < y, what must be true?

I) \(xy < 80\)

II) \(\frac{x}{y} > 1\)

III) \(x^{2} + y^{2} > 1\)

A) None
B) II only
C) III only
D) I and II only
E) II and III only


If x = -10 and y = -9, xy = 90, which is not less than 80. So I is not true.

If x = 0 and y = 1, x/y = 0, which is not greater than 1. So II is not true, either.

Likewise, if x = 0 and y = 1, x^2 + y^2 = 1, which is not greater than 1, so III is not true, either.

Answer: A
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If x < 10, y < 8, and x < y, what must be true?

I) xy<80
II) x/y>1
III) x^2+y^2>1

I. We know x<a , y<b => xy < ab only when x,y,a,b +ve
So we are almost sure this is not true
We know if we want product of 2 small numbers to be very large, we pick 2 negative numbers.
Here such that bgger than 80. Maybe 90. So -10 and -9.
x<y then x=-10 and y=-9
xy =90
So False.

II. x/y > 1
We are given x<y
So to flip the sign same and to get x/y>1. y should be -ve.
So pick a +ve y to prove false such that it suits our constraints.
x=2 and y=3 example

III.
x^2+y^2>1
Sum of two squares are greater than or equal to 0.
So we try to get x^2+y^2=0
But only possible when x=y=0. Not allowed.
lets try for x^2+y^2=1
x=0 y=1 suits our needs­
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