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N22J
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N22J
Actually you have one more choice of having both as well, so 3 more combinations

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Andy has to buy either a coke or a burger means he can choose 1 out of the 2 not both.
Is it correct?
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But the question says either or right? Which shoul mean only one out of the two right?

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If there were no restrictions at all, he'd be able to choose 5C3 = 5*4*3/3! = 10 different meals. The only one of these meals that doesn't include a burger or a coke is {pizza, fries, sandwich}. That leaves us with 10 - 1 = 9 meals that do include a burger or a coke (or both).

As the question is worded, I would not interpret the "or" as an "exclusive or", though I agree the question should be clearer about that. If you do assume that he can only buy one of the two foods (burger or coke, but not both), the answer is 6.
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N22J
A restaurant offers a $10-meal that consists of exactly three food items out of:
Burger, Sandwich, Pizza, French Fries, Coke
If Andy has to buy either a coke or a burger, in how many ways can he select his meal?
A. 3
B. 6
C. 9
D. 10
E. 12

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Assuming the either a coke or a burger in mean implies he can select only a burger or a coke out of the two= 2C1

Selecting remaining 2 food items out of Sandwich, Pizza, French Fries= 3C2

Therefore,number of ways in which he can select his mean=3C2*2C1= 6

Hope it helps!!
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Try this to understand "Either or"

From 1 to 50, how many numbers are divisible by either 2 or 5?

Will you count 10, 20,...or not?

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Try this to understand "Either or"

From 1 to 50, how many numbers are divisible by either 2 or 5?

Will you count 10, 20,...or not?
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N22J
Try this to understand "Either or"

From 1 to 50, how many numbers are divisible by either 2 or 5?

Will you count 10, 20,...or not?

Numbers divisible by 2 = (50-2)/2 + 1 = 25
Numbers divisible by 5= (50-5)/5 + 1 = 10

Numbers divisible by both 2 and 5 =ones divisible by 10= 5

So numbers are divisible by either 2 or 5 = 25+10-5 = 30

Here either or..means div by 2 + div by 5 - Not divisible by both
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