What is the probability that the sum of two dice rolls will yield anyt

Question

What is the probability that the sum of two dice rolls will yield anything but an 8?

A. 5/36
B. 1/6
C. 11/36
D. 25/36
E. 31/36

Kinshook · Answer

# of cases of sum of 2 dice yielding 8 = 62,26,53,35,44 = 5 cases
# of total cases = 6 * 6 = 36
# of favorable cases = Probability of 2 die yielding sum anything but 8 = 36 - 31
Probability = 31/36

IMO E

Lampard42 · Answer

Total Possibilities = 6(1st die)*6(2nd die) = 26
Possibilities for sum of 8 = 44,62,26,35,53 = 5
Probab. of not 8 = 1-5/36=31/36 IMO E

Archit3110 · Answer

total pairs ; 36
and getting 8 ; (2,6); (3,5) ( 4,4) ( 5,3) ( 6,2) ; 5
so not 8 ; 36-5; 31
P ; 31/36
IMO E

saukrit · Answer

For 8 as an outcome , u can have following pairs (2,6)(6,2)(3,5)(5,3)(4,4) = 5 pairs
Total possible outcome= 6*6=36
Total favorable outcome (we get anything but 8)= 36-5=31

Required probability= 31/36

IMO Answer must be E

CareerGeek · Answer

Probability of anything but 8 = 1 - Prob(Sum = 8)

Total outcomes = 36
Favourable outcomes = (2,6), (3,5), (4,4), (5,3), (6,2) = 5
—> Prob(Sum=8) = 5/36

Required Probability = 1 - 5/36 = 31/36

IMO Option E

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BrushMyQuant · Answer

We need to find What is the probability that the sum of two dice rolls will yield anything but an 8?

As we are rolling two dice => Number of cases =  6^2  = 36

Now lets find the number of cases where we will get 8 as the sum and we can subtract them from 36 to get the required cases
(2,6), (3,5), (4,4), (5,3), (6,2) = 5 outcomes

=> Cases in which we get anything but 8 = 36 - 5 = 31

=> Probability that the sum of two dice rolls will yield anything but an 8 =  \frac{31}{36}

So,  Answer will be E 
Hope it helps!

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What is the probability that the sum of two dice rolls will yield anyt

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