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Bunuel
Which two of the following numbers, when added together, yield a sum between 1 and 2?

I. \(\frac{7*2^3}{3^3-7}\)

II. \(\frac{\frac{3}{11}}{\frac{6}{11}}\)

III. \(\frac{-11^2-11^3}{30 * 44}\)

A. I only
B. II only
C. III only
D. I and III only
E. I, II and III

Question: Which two of the following numbers, when added together, yield a sum between 1 and 2?

I. \(\frac{7*2^3}{3^3-7}\)
\(\frac{7*2^3}{3^3-7}=\frac{7*2^3}{20}=\frac{14}{5} = 2.8\)

II. \(\frac{\frac{3}{11}}{\frac{6}{11}}\)
\(\frac{\frac{3}{11}}{\frac{6}{11}}=\frac{3}{6}=.5\)

III. \(\frac{-11^2-11^3}{30 * 44}\)
\(\frac{-11^2-11^3}{30 * 44}=-\frac{11^2(1+11)}{30*44}= -1.1\)

Adding together I & III =2.8 - 1.1 = 1.7

IMO D
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First, simplify the numbers

I) 56/20 = 2.8

II) 1/2 = 0.5

III) -11/10 = -1.1

Adding I & II = (2.8+0.5) > 2

Adding II & III = (0.5-1.1)< 1

Adding I & III = (2.8 - 1.1) < 2 and >1

Thus, (D)
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Bunuel
Which two of the following numbers, when added together, yield a sum between 1 and 2?

I. \(\frac{7*2^3}{3^3-7}\)

II. \(\frac{\frac{3}{11}}{\frac{6}{11}}\)

III. \(\frac{-11^2-11^3}{30 * 44}\)

A. I only
B. II only
C. III only
D. I and III only
E. I, II and III

I. \(\frac{7*2^3}{3^3-7}\)

\(= \frac{7*8}{20}=2.80\)

II. \(\frac{\frac{3}{11}}{\frac{6}{11}}\)

\(= \frac{3}{11}*\frac{11}{6}=0.50\)

III. \(\frac{-11^2-11^3}{30 * 44}\)

\(=\frac{11^2( -1 -11)}{30 * 44}=-1.10\)

Add I. and III, answer will be 1.70 , hence correct option will be (D)
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The question states "Which two of the following numbers, when added together....".
There is only one answer option (D) that is adding two of the provided numbers. In this case, can't we straightaway mark D?
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priyamitra
The question states "Which two of the following numbers, when added together....".
There is only one answer option (D) that is adding two of the provided numbers. In this case, can't we straightaway mark D?

Not necessarily. Statement 1+2+3 could have been between 1 &2 (you need to check to verify that it isn't). But I do agree; the question isn't framed very well.
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Deconstructing the Question

We must determine which two of the expressions produce a sum between

\(1\) and \(2\).

So we evaluate each value and test their sums.

Step-by-step

Evaluate expression I

\(\frac{7 \cdot 2^3}{3^3 - 7}\)

\(2^3 = 8\)

\(3^3 = 27\)

\(\frac{7 \cdot 8}{27 - 7}\)

\(\frac{56}{20}\)

\(= 2.8\)

Evaluate expression II

\(\frac{\frac{3}{11}}{\frac{6}{11}}\)

\(= \frac{3}{11} \times \frac{11}{6}\)

\(= \frac{3}{6}\)

\(= 0.5\)

Evaluate expression III

\(\frac{-11^2 - 11^3}{30 \cdot 44}\)

\(11^2 = 121\)

\(11^3 = 1331\)

\(-121 - 1331 = -1452\)

\(30 \cdot 44 = 1320\)

\(\frac{-1452}{1320} \approx -1.1\)

Now test the sums

\(I + II = 2.8 + 0.5 = 3.3\)

\(I + III = 2.8 - 1.1 \approx 1.7\)

\(II + III = 0.5 - 1.1 = -0.6\)

Only \(I + III\) gives a value between \(1\) and \(2\)

Answer D: I and III only
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