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Bunuel
If the a-th term of a certain sequence is given by \((-1)^a + (-0.1)^a,\) then the sum of the terms from 1 to 5 is

A. -1.11111
B. -1.09091
C. 0
D. 0.90909
E. 1.11111

When a is 1:

-1 + (-0.1)

When a is 2:

1 + 0.01

When a is 3:

-1 + (-0.001)

When a is 4:

1 + (0.0001)

When a is 5:

-1 + (-0.00001)

We see that the sum of integer parts of the first 5 terms is:

-1 + 1 + (-1) + 1 + (-1) = -1

And the sum of the decimal parts of the first 5 terms is:

-0.1 + 0.01 + (-0.001) + 0.0001 + (-0.00001) = -0.09 + (-0.0009) + (-0.00001) = -0.09091

Therefore, the sum of the first 5 terms is:

-1 + (-0.09091) = -1.09091

Answer: B
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Bunuel
If the a-th term of a certain sequence is given by \((-1)^a + (-0.1)^a,\) then the sum of the terms from 1 to 5 is

A. -1.11111
B. -1.09091
C. 0
D. 0.90909
E. 1.11111
Solution:

  • First Term
  • \((-1)^a=(-1)^1+(-1)^2+(-1)^3+(-1)^4+(-1)^5=-1+1-1+1-1=-1\)

  • Second Term
  • \((-0.1)^a=(-0.1)^1+(-0.1)^2+(-0.1)^3+(-0.1)^4+(-0.1)^5=-0.1+0.01-0.001+0.0001-0.00001=-0.09091\)

  • Adding them, we get \(-1-0.09091=-1.09091\)

Hence the right answer is Option B
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