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Bunuel
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Coins worth $60.00 are divided into two piles. If one pile is worth $1 13 Aug 2019, 02:59
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C
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Question Stats:

100% (00:55) correct 0% (00:00) wrong based on 41 sessions

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Coins worth $60.00 are divided into two piles. If one pile is worth $12.00 more than the other, what is the worth of the smaller pile?

A. $5.00
B. $12.00
C. $24.00
D. $36.00
E. $72.00
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Official Answer
C
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Coins worth $60.00 are divided into two piles. If one pile is worth $1 13 Aug 2019, 03:01
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X+X+12=60
2X=48
X=24
Option C

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Coins worth $60.00 are divided into two piles. If one pile is worth $1 13 Aug 2019, 03:03
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Bunuel
Coins worth $60.00 are divided into two piles. If one pile is worth $12.00 more than the other, what is the worth of the smaller pile?

A. $5.00
B. $12.00
C. $24.00
D. $36.00
E. $72.00
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Given: Coins worth $60.00 are divided into two piles.

Asked: If one pile is worth $12.00 more than the other, what is the worth of the smaller pile?

Let the worth of smaller pile be s

s + (s + 12) = 60
s=24

IMO C
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Coins worth $60.00 are divided into two piles. If one pile is worth $1 13 Aug 2019, 07:34
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We have pile X and pile Y, and together they add up to $60.

X + Y = 60

One pile is worth $12 more than the other.

X = Y + 12

Now we just substitute for X in the first equation

(Y + 12) + Y = 60
2Y = 48
Y = 24

Answer (C)
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Coins worth $60.00 are divided into two piles. If one pile is worth $1 20 Sep 2019, 02:30
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Bunuel
Coins worth $60.00 are divided into two piles. If one pile is worth $12.00 more than the other, what is the worth of the smaller pile?

A. $5.00
B. $12.00
C. $24.00
D. $36.00
E. $72.00
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Official Explanation



We have coins and piles, but this question is more about piles. The answer choices look friendly, so let's work with those. Say we take (B). If the smaller pile is $12, then the larger pile is $12 + $12 = $24 but that would yield a total of $36, not $60. That smaller pile is too small. Looking at (D), $36 doesn't make sense as a smaller pile, because it's already more than half of $60. Therefore, the correct answer for the smaller pile must be the one between these possibilities, $24. We can check: $24 + $36 = $60.

The correct answer is (C).
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Coins worth $60.00 are divided into two piles. If one pile is worth $1 20 Sep 2019, 02:31
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Bunuel
Coins worth $60.00 are divided into two piles. If one pile is worth $12.00 more than the other, what is the worth of the smaller pile?

A. $5.00
B. $12.00
C. $24.00
D. $36.00
E. $72.00
Show more

Video Explanation



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