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13 Aug 2019, 02:59
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C
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Coins worth $60.00 are divided into two piles. If one pile is worth $12.00 more than the other, what is the worth of the smaller pile?
A. $5.00
B. $12.00
C. $24.00
D. $36.00
E. $72.00
A. $5.00
B. $12.00
C. $24.00
D. $36.00
E. $72.00
13 Aug 2019, 03:01
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X+X+12=60
2X=48
X=24
Option C
Posted from my mobile device
2X=48
X=24
Option C
Posted from my mobile device
13 Aug 2019, 03:03
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Bunuel
Coins worth $60.00 are divided into two piles. If one pile is worth $12.00 more than the other, what is the worth of the smaller pile?
A. $5.00
B. $12.00
C. $24.00
D. $36.00
E. $72.00
A. $5.00
B. $12.00
C. $24.00
D. $36.00
E. $72.00
Given: Coins worth $60.00 are divided into two piles.
Asked: If one pile is worth $12.00 more than the other, what is the worth of the smaller pile?
Let the worth of smaller pile be s
s + (s + 12) = 60
s=24
IMO C
