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04 Sep 2019, 12:49
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
65% (01:20) correct
35%
(00:56)
wrong
based on 141
sessions
History
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04 Sep 2019, 13:10
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84=2² × 3×7
The number of factors:(2+1)*(1+1)*(1+1)=12
3,7,21,and 1 are odd.
So,12-4=8
Option C
Posted from my mobile device
The number of factors:(2+1)*(1+1)*(1+1)=12
3,7,21,and 1 are odd.
So,12-4=8
Option C
Posted from my mobile device
04 Sep 2019, 16:08
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\(84=2^2*3*7\)
Any factor of 84 can be written in the form of \(2^a*3^b*7^c\), where 0≤a≤2, 0≤b≤1 and 0≤c≤1 and a,b and c are integers
We want to know only even factors.
Hence a can take 2 values 1 or 2
b can take 2 values 0 or 1
c can take 2 values 0 or 1
Total even factors= 2*2*2=8
Any factor of 84 can be written in the form of \(2^a*3^b*7^c\), where 0≤a≤2, 0≤b≤1 and 0≤c≤1 and a,b and c are integers
We want to know only even factors.
Hence a can take 2 values 1 or 2
b can take 2 values 0 or 1
c can take 2 values 0 or 1
Total even factors= 2*2*2=8
AbdulMalikVT
