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40%-30%+(40%×-30%)= 40%-30%-12%=98%
OptionB

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Solution



Given
    • The value of a certain stock rose by 40 percent from March to April
    • Value of stock decreased by 30 percent from April to May

To find
    • The stock’s value in May was what percent of its value in March?

Approach and Working out

Let stock’s value in March is x.
Hence, stock’s value in April = 1.4 x(40% increment)
Hence, stock’s value in May = 0.7* (1.4 x)(30% decrement) = 0.98 x

0.98x is 98% of x.
    • Hence, stock’s value in May was 98% percent of its value in March.

Thus, option B is the correct answer.

Correct Answer: Option B
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Method -2

Since percentage change is applied twice on a single quantity, it is a case of the successive percentage change.

    • So, total percentage change in the Stock value= 40 -30 + 40*(-30)/100 = 10 -12= -2%
    • So, the net change is of -2%.
    • Hence, the stock’s value in May is 100-2 = 98% of stocks value in March

Thus, option B is the correct answer.

Correct Answer: Option B
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Let's say the initial value is 100

The stock rose by 40%, so 100 x .4 = 40
100 + 40 = 140
The stock then decreased by 30%, so 140 x .3 = 42
140 - 42 = 98

Answer = 98%
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Bunuel
The value of a certain stock rose by 40 percent from March to April, and then decreased by 30 percent from April to May. The stock’s value in May was what percent of its value in March?

A. 90%
B. 98%
C. 110%
D. 130%
E. 142%

\(+40 - 30 + \frac{(40)(-30)}{100}\)

\(= 10 - 12\)

\(= -2\)

Hence, stock’s value in May was what percent of its value in March is 100 -2 = 98% , Answer must be (B)
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