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[GMAT math practice question]

\(f(x)\) denotes the number of prime numbers less than or equal to a positive integer \(x\), and \(m(a, b)\) denotes the maximum of \(a\) and \(b.\) What is the summation of all the values of \(x\) which satisfy \(m(f(x), 5)=5\)?

\(A. 70\)

\(B. 72\)

\(C. 74\)

\(D. 76\)

\(E. 78\)

any good explanation for this question??
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=>

Since \(m(f(x),5)=5\), we have \(f(x) ≤ 5\) or \(f(x) = 0, 1, 2, 3, 4\) or \(5.\)

\(f(1) = 0, f(2) = 1, f(3) = 2, f(4) = 2, f(5) = 3, … , f(11) = 5, f(12) = 5, f(13) = 6. f(13) = 6\) is out of the range of \(f(x) ≤ 5.\)
So, all possible values of \(x\) are \(1, 2, 3, … , 12\) and we have \(1 + 2 + 3 + … + 12 = 78\).

Therefore, E is the answer.
Answer: E
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F(x) ———-> gives the count of all the Primes less than or equal to X


Max of ( f(x). ; 5) = 5

This means every value of X that will satisfy this function must have 5 or less prime values that are less than or equal to X

First 5 prime numbers
2, 3, 5, 7, 11

Next prime number 13——-> f(13) = 6 prime numbers including 13

If x = 13, the max number would be 6, not 5

Thus every Positive integer from 1 thru 12, inclusive, will satisfy X

Then just need to sum the first 12 consecutive integers

(12) (13) * (1/2) = 78

E

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