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ann1111
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But if it's mentioned that if one matchstick falls, the whole string will fall, why will there be any other cases?

The question is not worded correctly, but I assume it's trying to say that for each of the ten matchsticks, there is a 0.04 probability the matchstick falls. So there are really eleven different cases -- zero matchsticks fall, one matchstick falls, two matchsticks fall, and so on, up to all ten falling. If you wanted to solve this problem directly, you would need to add ten different probabilities -- the probability that one falls, the probability that two fall, the probability that three fall, and so on, since in every one of those ten cases, the string of matches will fall. Most of those probabilities are difficult to calculate (you would need to use binomial probability concepts), which is why I solved the question by finding the probability that no matches fall, then subtracted that from 1.
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