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11 Mar 2020, 04:30
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
5%
(low)
Question Stats:
93% (01:16) correct
7%
(02:08)
wrong
based on 484
sessions
History
Date
Time
Result
Not Attempted Yet
A 400 milliliter solution is 20% alcohol by volume. If 100 milliliters of water is added, what is the new concentration of alcohol, as a percent of volume?
(A) 5%
(B) 10%
(C) 12%
(D) 12.5%
(E) 16%
(A) 5%
(B) 10%
(C) 12%
(D) 12.5%
(E) 16%
11 Mar 2020, 06:05
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Bunuel
A 400 milliliter solution is 20% alcohol by volume.
20% of 400 = 80
So, the original solution contains 80 milliliters of alcohol
If 100 milliliters of water is added...
400 + 100 = 500
So, our NEW solution has a total volume of 500 milliliters
...what is the new concentration of alcohol, as a percent of volume?
NEW concentration of alcohol = 80/500
Divide top and bottom of our fraction by 5 to get: 16/100, which is the same as 16%
Answer: E
Cheers,
Brent
11 Mar 2020, 10:11
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Bunuel
Water = 80% of 400 => 320
Alcohol = 20% of 400 => 80
Total Mixture = 400
After adding 100 ml of water -
Water = 80% of 400 +100 => 420
Alcohol = 20% of 400 => 80
Total Mixture = 500
So, the new concentration of alcohol, as a percent of volume?
= 80/500*100
= 16%, Thus Answer must be (E)
