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Ravixxx
If \(\frac{a}{|a|}\) < a and a≠o, then which of the following cannot be true?

(A) \(a>1\)
(B) \(a<-1\)
(C) \(|a|>1\)
(D) \(\frac{a}{|a|}=1\)
(E) \(\frac{a}{|a|}=-1\)


Source: Ready4Gmat.

If a > 0, then \(\frac{a}{|a|} = 1\) and we would be given \(1 < a\), therefore \(a > 1\) describes all the positive solutions.

If a < 0, then \(\frac{a}{|a|} = -1\) and we would be given \(-1 < a\). Therefore \(-1 < a < 0\) is the only region for negative a's.

Then note the question is asking for "which of the following CANNOT BE TRUE", we have to find a region that has absolutely no solutions.
(A) \(a>1\), this is the solution for positive a's.
(B) \(a<-1\), we don't have any solution that satisfies this so this is our answer.
(C) \(|a|>1\), when a is positive we can satisfy this.
D and E refer to the case "a is positive" and "a is negative", there are solutions for both cases.

Ans: B
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Ravixxx
If \(\frac{a}{|a|}\) < a and a≠o, then which of the following cannot be true?

(A) \(a>1\)
(B) \(a<-1\)
(C) \(|a|>1\)
(D) \(\frac{a}{|a|}=1\)
(E) \(\frac{a}{|a|}=-1\)


Source: Ready4Gmat.


The ALGEBRAIC approach...
\(\frac{a}{|a|}<a........|a|a>a.......a(|a|-1)>0\)...
Two cases..
1) a>0, then |a|>1....a>1......A, C and D can be true....
2) a<0, then |a|<1...But as a<0...-1<a<0, so B cannot be true and E can be true

B
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I did this algebraically
a(1/modA - 1) < 0

--> a < 0

(or)

--> 1/modA < 1 ==> modA > 1

but clearly a can be greater than 1 ; where am I going wrong ; any help please, and how to learn these concepts
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RamaSubramanian
If \(\frac{a}{|a|} < a\) and a ≠ 0, then which of the following cannot be true?

(A) \(a>1\)

(B) \(a<-1\)

(C) \(|a|>1\)

(D) \(\frac{a}{|a|}=1\)

(E) \(\frac{a}{|a|}=-1\)

I did this algebraically
a(1/modA - 1) < 0

--> a < 0

(or)

--> 1/modA < 1 ==> modA > 1

but clearly a can be greater than 1 ; where am I going wrong ; any help please, and how to learn these concepts

Here is an easier way to do it.

If a > 0, then |a| = a, and we get a/a < a, which simplifies to 1 < a.

If a < 0, then |a| = -a, and we get a/(-a) < a, which simplifies to -1 < a. Since we're considering the a < 0 range, this gives -1 < a < 0.

So, if a > 0, then options A, C, and D could be true. If -1 < a < 0, then E could be true. Only B is never true.

Answer: B.
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