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06 May 2020, 10:57
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B
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Difficulty:
25%
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Question Stats:
80% (02:32) correct
20%
(02:38)
wrong
based on 193
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In two days of canoeing, Nina traveled a total distance of 64 kilometers and spent a total of 18 hours canoeing. On the second day, Nina canoed 2 hours longer and at an average speed 1 kilometer per hour faster than she canoed on the first day. What was Nina’s average speed on the first day?
(A) 2 kilometers per hour
(B) 3 kilometers per hour
(C) 4 kilometers per hour
(D) 5 kilometers per hour
(E) 6 kilometers per hour
(A) 2 kilometers per hour
(B) 3 kilometers per hour
(C) 4 kilometers per hour
(D) 5 kilometers per hour
(E) 6 kilometers per hour
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06 May 2020, 13:51
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BrentGMATPrepNow
18 hours = divided into 8 hours (day 1) & 10 hours (day 2)
if day 1 speed is x kph, then
8x + 10 (x + 1) = 64
or, 18x = 54
or, x = 3 (option B)
10 May 2020, 15:43
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BrentGMATPrepNow
Nina traveled a total distance of 64 kilometers and spent a total of 18 hours canoeing. On the second day, Nina canoed 2 hours longer and at an average speed 1 kilometer per hour faster than she canoed on the first day.
Let h = # of hours canoed on first day
So, h + 2 = # of hours canoed on second day
We can write: h + (h + 2) = 18
Simplify: 2h + 2 = 18
Solve: h = 8
So Nina traveled for 8 hours on the first day and for 10 hours on the second day
Nina traveled a total distance of 64 kilometers. Nina canoed at an average speed 1 kilometer per hour faster than she canoed on the first day.
Let x = Nina's speed (in kilometres per hour) on the first day
So, x + 1 = Nina's speed (in kilometres per hour) on the second day
distance = (time)(speed)
Let's start with the following word equation: (distance traveled on the first day) + (distance traveled on the second day) = 64
Substitute to get: ((8)(x)) + ((10)(x + 1)) = 64
Simplify: 8x + 10x + 10 = 64
Simplify: 18x + 10 = 64
Subtract 10 from both sides: 18x = 54
Divide both sides by 18 to get: x = 3
So, Nina's speed on day one was 3 kilometres per hour
Answer: B
Cheers,
Brent
