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Bunuel
What is the greatest integer that is the sum of two different prime numbers, each of which is less than 50 ?

A. 47
B. 90
C. 94
D. 96
E. 99


PS20428

For the sum to be maximum, the prime numbers must be maximum possible.
    Prime numbers must be less different and less than 50.
    Two maximum prime numbers which are less than 50 are 47 and 43
      47+43 = 90.
Answer: Option B
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Bunuel
What is the greatest integer that is the sum of two different prime numbers, each of which is less than 50 ?

A. 47
B. 90
C. 94
D. 96
E. 99


PS20428

prime number can be checked ; 6n+/-1 ;
n=8 ; 47 and n=7 ; 43
47+43 ; 90
OPTION B
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B?

47 + 43 = 90

Greatest sum: when two numbers added are greatest.

Both are the greatest prime number < 50
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Solution


To Find
    • Greatest value of the sum of two different prime numbers, each of which <50.

Approach and Working Out
Let’s consider the two numbers be ‘a’ and ‘b’.
    • Sum = a+b. Both a and b must be prime and must be <50.
    • For sum to be greatest, both a and b should be maximum.
      o Thus we need to find two distinct prime numbers which are immediately less than 50
    .
We know that all prime numbers greater than 3 are of the form 6k +1 or 6k-1 and are thus odd as well.
    • Checking for 49, \(49 = 7^2\), thus is not a prime number.
    • Checking for 47, we cannot prime factorize it to any prime factor <47. Thus it is prime.
    • Checking for 45, \(45 = 5*3^2\), thus is not a prime.
    • Checking for 43, we cannot prime factorize it to any prime factor <43. Thus it is prime.

Thus the two greatest primes which are less than 50 are 43 and 47.
Sum = 47 + 43 = 90

Correct Answer: Option B
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how to find if a number is a prime number?
check divisibility for all nos till the closest perfect sq of that number
for eg: to check if 47 has any factor check all nos from 1 to 7 and 7^2 =49 (closest sq to 47)
no number between 1 to 7 is divisible by 47; hence no need to check further. 47 is a Prime.
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Solution


To Find
    • Greatest value of the sum of two different prime numbers, each of which <50.

Approach and Working Out
Let’s consider the two numbers be ‘a’ and ‘b’.
    • Sum = a+b. Both a and b must be prime and must be <50.
    • For sum to be greatest, both a and b should be maximum.
      o Thus we need to find two distinct prime numbers which are immediately less than 50
    .
We know that all prime numbers greater than 3 are of the form 6k +1 or 6k-1 and are thus odd as well.
    • Checking for 49, \(49 = 7^2\), thus is not a prime number.
    • Checking for 47, we cannot prime factorize it to any prime factor <47. Thus it is prime.
    • Checking for 45, \(45 = 5*3^2\), thus is not a prime.
    • Checking for 43, we cannot prime factorize it to any prime factor <43. Thus it is prime.

Thus the two greatest primes which are less than 50 are 43 and 47.
Sum = 47 + 43 = 90

Correct Answer: Option B
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43+47=90
Answer: D
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Prime numbers up to 100 (useful to memorize): \(2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97\)


\(43 + 47 = 90\)

Answer is B.
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