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IMO C

a^(2/3) = b^(2/3) can be written as (a^(1/3))^2 = (b^(1/3))^2.

Rule: 1. (a^m)^n = a^(mn)
2. a number with an even power is always positive. However, a, b can either be positive or negative.

Using Rule 2 , Only St 1 and St 2 will satisfy.

Thanks
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Hi,

Whenever we use square root on variable, we consider the +ve root so why for III sentence -ve root is also considered in solutions?
Bunuel
If \(a^{\frac{2}{3}}=b^{\frac{2}{3}}\) for \(a ≠ 0\) and \(b ≠ 0\), then which of the following statements must be true?


I. \((\frac{a}{b})^2=1\)

II. \(a^2=b^2\)

III. \(\sqrt{a}=\sqrt{b}\)

A. I only
B. II only
C. I and II only
D. II and III only
E. I, II, and III
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Akhilesh1227
Hi,

Whenever we use square root on variable, we consider the +ve root so why for III sentence -ve root is also considered in solutions?
The rule is that, where \(a\) is non-negative, \(\sqrt{a}\) will always be positive, for eg. \(\sqrt{9} = 3\), it cannot be \(-3\). In the rule you're referring to, we are given \(a\) to be a non-negative integer, hence the result of that is positive. If \(a\) were negative, then the result of \(\sqrt{a}\) is an imaginary number.

In the question asked, we don't know the signs of \(a\) and \(b\), so if \(b\) is negative, and \(a\) is positive, then \(\sqrt{b}\) will be an imaginary number, and will not be equal to \(\sqrt{a}\). Hope it helps.
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Hi krunaal

Thanks for the explanation
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