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03 Jul 2020, 05:37
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
15%
(low)
Question Stats:
77% (00:54) correct
23%
(01:43)
wrong
based on 115
sessions
History
Date
Time
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Not Attempted Yet
A certain code contains five letters, including one A, two B, and 2 C. In how many possible ways can we create the codes?
(A) 5
(B) 10
(C) 12
(D) 30
(E) 60
(A) 5
(B) 10
(C) 12
(D) 30
(E) 60
Updated on: 03 Jul 2020, 05:52
Originally posted by hsingh3031 on 03 Jul 2020, 05:40.
Last edited by hsingh3031 on 03 Jul 2020, 05:52, edited 1 time in total.
Last edited by hsingh3031 on 03 Jul 2020, 05:52, edited 1 time in total.
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30 is the answer
Total arrangement of 5 letter = 5!
Repetition of B & C digits are 2 times
its 5! / 2! * 2!
= 30
Total arrangement of 5 letter = 5!
Repetition of B & C digits are 2 times
its 5! / 2! * 2!
= 30
03 Jul 2020, 05:46
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Explanation:
Total arrangement of 5 letter = 5!
Repeatability of B & C digits are 2 times
Possible ways = 5!/2!*2! = 30
IMO-D
Total arrangement of 5 letter = 5!
Repeatability of B & C digits are 2 times
Possible ways = 5!/2!*2! = 30
IMO-D
