If xy 10^3, then the value of

Question

If xy >  10^3 , then the value of  (y+\frac{1}{x})/6y  is closest to which of the following?​

A. 0.13​

B. 0.17​

C. 0.2​

D. 0.25​

E. 0.28

yashikaaggarwal · Answer

(Y+(1/x))/6y
((XY+1)/x)/6y
XY+1/6Xy
Let XY be 10^4
10^4+1/6*10^4
10^4/6*10^4
1/6
0.166
O.17

Answer is B

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dimri10 · Answer

Using algebra the equation is actually XY+1/6xy so it is very close to XY/6xy or 1/6 or 0.17

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daniformic · Answer

xy>10^3 and (Y+(1/x))/6y
If x=100 and y=100 
(100+1/100)/600
100,01/600=≅1/6
 Answer -> B

Babineaux · Answer

Given,

(y+\frac{1}{x})\frac{1}{6y}

=  \frac{(xy+1)}{x}\frac{1}{6y}

=  \frac{(xy+1)}{6xy}

Now,  xy  >  10^3  which means,  10^3  +  1  ~=  10^3

Hence, the whole expression reduces to  \frac{10^3}{6*10^3}  =  \frac{1}{6}  =  0.1666  =  0.17

IMO B

rajatchopra1994 · Answer

Explanation:

{(y+1/x)/6y}
1/6 + 1/6xy
= 0.166 + 1/6x10^3
it will be close to 0.17

IMO-B

ScottTargetTestPrep · Answer

Solution:

Multiplying the expression by x/x, we have:

(xy + 1) / (6xy) = xy / (6xy) +1 / (6xy) = 1/6 + 1/(6xy)

Since xy > 10^3 = 1000, then 1/(6xy) < 1/6000, which is quite small when compared to 1/6. Therefore, the expression is approximately equal to 1/6 or 0.1666…. Therefore, 0.17 is the closest to the value of the expression.

Answer: B

If xy > 10^3, then the value of

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