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555-605 (Medium)|   Algebra|      
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For any positive x, y z and k, if kx is n% of y, then what percentage 25 Jul 2020, 12:54
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A
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25% (medium)

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72% (01:36) correct 28% (02:01) wrong based on 190 sessions

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For any positive x, y z and k, if kx is n% of y, then what percentage must be x of y?
a) (n/k)%
b) (n+k)%
c) (nk)%
d) (n-k)%
e) (100*n/k)%
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A
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For any positive x, y z and k, if kx is n% of y, then what percentage 25 Jul 2020, 13:15
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\(kx = (\frac{n}{100})*y\)

\(x = (\frac{n}{k*100})*y\)

x = \((\frac{n}{k})\)% of y


globaldesi
For any positive x, y z and k, if kx is n% of y, then what percentage must be x of y?
a) (n/k)%
b) (n+k)%
c) (nk)%
d) (n-k)%
e) (100*n/k)%
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For any positive x, y z and k, if kx is n% of y, then what percentage 26 Jul 2020, 01:01
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globaldesi
For any positive x, y z and k, if kx is n% of y, then what percentage must be x of y?
a) (n/k)%
b) (n+k)%
c) (nk)%
d) (n-k)%
e) (100*n/k)%
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Solution


    • x, y, and k are positive integers.

    • n% of y = kx

      o \(⟹ y*\frac{n}{100} = kx \)

      o \(⟹ y*\frac{n}{k*100} = x \)

         This means, x is \(\frac{n}{k}\) % of y

Thus, the correct answer is Option A.
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For any positive x, y z and k, if kx is n% of y, then what percentage 26 Jul 2020, 02:07
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globaldesi
For any positive x, y z and k, if kx is n% of y, then what percentage must be x of y?
a) (n/k)%
b) (n+k)%
c) (nk)%
d) (n-k)%
e) (100*n/k)%
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Asked: For any positive x, y z and k, if kx is n% of y, then what percentage must be x of y?

kx = ny/100

x/y = n/100k = (n/k) %

IMO A
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For any positive x, y z and k, if kx is n% of y, then what percentage 26 Jul 2020, 07:46
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For any positive x, y z and k, if kx is n% of y, then what percentage must be x of y?
a) (n/k)% --> correct: if kx is n% of y i.e. kx = n% of y= (n/100)*y => x = ny/(100k) ---(i). Now let's say p% of y =x i.e. (p/100)*y=x, replacing the value of x from eq.(i), (p/100)*y=x=ny/(100k) => p=n/k i.e. p% = (n/k)%
b) (n+k)%
c) (nk)%
d) (n-k)%
e) (100*n/k)%
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For any positive x, y z and k, if kx is n% of y, then what percentage 24 Oct 2024, 23:43
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