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12 Oct 2020, 10:19
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Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
79% (01:52) correct
21%
(02:08)
wrong
based on 89
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Line K is defined by the equation 2x + 3y = -4, and line L is defined by the equation 4x - 5y = 3. If the point (m, n) is the intersection of lines K and L, what is the value of m + n?
A) -2.5
B) -2
C) -1.5
D) -1
E) -0.5
A) -2.5
B) -2
C) -1.5
D) -1
E) -0.5
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12 Oct 2020, 10:55
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Solving both the equations should give us the intersection point (m,n)
4x+6y=-8
4x-5y=3
N=y=-1
M =X=-0.5
M+N=-1.5
Posted from my mobile device
4x+6y=-8
4x-5y=3
N=y=-1
M =X=-0.5
M+N=-1.5
Posted from my mobile device
12 Oct 2020, 13:56
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BrentGMATPrepNow
Since (m, n) is on both lines, you can plug x = m and y = n into both lines to get two equations.
→ 2m + 3n = -4
→ 4m – 5n = 3
We have a system of equations. We can solve by multiplying the first equation by 2 and then subtracting the equations.
→ 4m + 6n = -8
→ 4m – 5n = 3
→ -----------------
→ 11n = -11
When you solve, you get n = -1. Plug this into either equation to find m.
→ 2m + 3n = -4
→ 2m + 3(-1) = -4
→ 2m – 3 = -4
→ 2m = -1
→ m = -0.5
Therefore, the answer is
→ m + n = -0.5 + (-1) = -1.5.
