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Solution



Given
In this question, we are given that
    • The values of |r| and |s| are not equal

To find
We need to determine
    • The value of the given expression \(\frac{r^2+2rs+s^2}{r^2-s^2}\)

Approach and Working out
Simplifying the numerator and the denominator individually,
    • \(r^2 + 2rs + s^2 = (r + s)^2 = (r + s) (r + s)\)
    • \(r^2 – s^2 = (r + s) (r – s)\)

Hence, the value = \(\frac{(r + s) (r + s)}{(r + s) (r – s)} = \frac{(r + s)}{(r – s)}\)
[here, we can cancel (r + s) as we already know |r| is not equal to |s|]

Thus, option A is the correct answer.

Correct Answer: Option A
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Asked: If |r| ≠ |s|, then \(\frac{r^2+2rs+s^2}{r^2-s^2}\) is equivalent to which of the following?

\(r^2+2rs+s^2 = (r+s)^2\)
\(r^2 - s^2 = (r+s)(r-s)\)

\(\frac{r^2+2rs+s^2}{r^2-s^2}= \frac{(r+s)^2}{(r+s)(r-s)}= \frac{r+s}{r-s}\)
It is given that \(r \neq s\) since \(|r| \neq |s|\)

IMO A
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