Bunuel
12 men cam complete a piece of work in 36 days, 18 women can complete the same piece of work in 60 days. 8 men and 20 women work together for 20 days. If only women were to complete the remaining piece of work in 4 day, how many women would be required?
A. 70
B. 66
C. 40
D. 34
E. 28
12 men take 36 days
12 men in 1 day do \(\frac{1}{36}\) th of the work
1 man in 1 day does \(\frac{1}{12*36}\)
8 men in 1 day does \(8 * \frac{1}{12 * 36} = \frac{1}{54}\)
18 women take 60 days
18 women in 1 day do \(\frac{1}{60}\) th of the work
1 woman in 1 day does \(\frac{1}{18*60}\)
20 women in 1 day does \(20 * \frac{1}{18 * 60} = \frac{1}{54}\)
8 men and 20 women in 1 day does \(\frac{1}{54} + \frac{1}{54} = \frac{1}{27}\)th of the work
Work done in 20 days = \(20 * \frac{1}{27} = \frac{20}{27}\)th of the work
The remaining work = 1 - \(\frac{20}{27} = \frac{7}{27}\)
Using the concept of MAN DAYS = \(\frac{M_1 * T_1}{W_1} = \frac{M_2 * T_2}{W_2}\)
M1 = 1, T1 = 1, W1 = Work done by 1 woman in 1 day\(\frac{1}{18 * 60}\)
M2 = x, T1 = 4, W2 = Work done by x woman in 4 days to finish\(\frac{7}{27}\)th of the work
\(\frac{1 * 1}{\frac{1}{18*60}} = \frac{x * 4}{\frac{7}{27}}\)
\(18 * 60 = \frac{x * 4 * 27}{7}\)
\(x = \frac{18 * 60 * 7}{4 * 27} = 70\)
Option AArun Kumar