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nityakaul02
I can not understand how the integral margin is divided


nityakaul02

The question is asking the minimum number of votes by which the winner could have won from the person who came second.

Let total votes be 100
Given that the person who lost got 30 , now remaining 70 votes

if remaining two people both got 35 votes then we have a draw. So the winner must get minimum 36 votes to have a majority of votes and win then the other person will get 70-36 =34 votes

Hence the minimum vote by which the winner can win from the nearest rival is 2.


Can you make the difference of votes between and winner and runner up less than 2? No.

Hence 2 is the most minimum margin by which the winner can win.

Ans-B

Hope it's clear.
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Can the margin not be 1 vote?

Say there are 50 voters; if 30% vote for the losing candidate, they get 15 votes.
That leaves 70% or 35 votes to be divided among the top two candidates. The smallest margin of victory would be when one gets 36% of the votes and the other gets 34% of the votes, or 50(.36)=18 votes, and 50(.34)=17 votes.

What am I missing?
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kkang98
Can the margin not be 1 vote?

Say there are 50 voters; if 30% vote for the losing candidate, they get 15 votes.
That leaves 70% or 35 votes to be divided among the top two candidates. The smallest margin of victory would be when one gets 36% of the votes and the other gets 34% of the votes, or 50(.36)=18 votes, and 50(.34)=17 votes.

What am I missing?

kkang98,
You have to find the smallest margin in terms of number of votes ( integers) and NOT in terms of percentage.
In terms of percentage one could also divide the remaining percentage in 35.1% and 34.9%, however in these case number of votes won't be an integer.

Hence instead of finding narrowest margin in terms of percentage try finding narrowest margin in terms of number of votes and see if you can get 1 vote margin!

Choose an easy number so that the winner and runner up can have equal number of votes and then try finding the margin.

Hope this helps.
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stne
If total number of voters are 10, then margin should be 1.
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urmi760
stne
If total number of voters are 10, then margin should be 1.
urmi

Not possible
Please show your working how you arrived at 1.
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stne
Total number of voters = 10
One candidate got 30% votes = 3votes
Out of remaining 7 votes, winner will get 4votes (40%) and other will get 3 votes (30%).
It's not mentioned that no two candidates can have same number of votes.

Isn't this correct?
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urmi760
stne
Total number of voters = 10
One candidate got 30% votes = 3votes
Out of remaining 7 votes, winner will get 4votes (40%) and other will get 3 votes (30%).
It's not mentioned that no two can have candidates same number of votes.

Isn't this correct?

urmi760,

Remember there is a winner, nearest rival and person who got 30% votes.
We have to find the narrowest margin between winner and nearest rival.

I believe the phrase " led by the nearest rival " means " nearest rival is leading from among the non winners. Hence person who got 30% votes and nearest rival cannot have same number of votes.

Maybe question could have been better framed to avoid such ambiguity.

Try tagging an expert and see if they can help.

Hope this helps to some extent.
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My answer is coming out to be 1.
What if we assume 50 people to be voting, in that case:

Losing candidate will get 15 votes (30%), winning candidate will get 18 votes (36%) and the third person will get 17 votes (34%).
Minimum absolute margin in such a case will be 18-17 = 1.
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IMO, if there is no mention of how many voters there actually are or any further information to justify an answer of 2, then the minimum absolute margin will be 1 as 1 is a possibility. For example, with 50 voters, the minimum absolute margin is 1 vote.
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ayushbhardwaj
ronakm94

Absolute margin of votes here is asked in the way of percentage,
so if 50 votes, 1 vote is margin
Percentage margin = 1/50 * 100 % = 2%

Hence, OA is (B).
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Deconstructing the Question

There are \(3\) candidates.

The losing candidate got \(30\%\) of the votes.

So the other two candidates together got

\(70\%\)

We need the minimum possible absolute margin of votes between the winner and the nearest rival, given that each candidate received an integral percent of votes.

Step-by-step

To minimize the winner's lead over the nearest rival, split the remaining \(70\%\) as evenly as possible.

The equal split would be

\(35\% \text{ and } 35\%\)

but then there would be no winner.

So the closest possible unequal integral split is

\(36\% \text{ and } 34\%\)

Thus the minimum percentage lead is

\(36-34=2\%\)

Now convert this into absolute votes.

Using a total of \(100\) votes gives

\(30,\ 34,\ 36\)

which are all integers and satisfy the conditions.

So the absolute margin is

\(36-34=2\)

Answer B
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