Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Sep 1507:00 PM EDT
-09:00 PM EST
Elite scores are possible when you enroll in a powerful GMAT course, taught live online + 6 months access to TTP OnDemand video courses included! Class starts Tues/Thurs Sept. 15, 2026 - Nov. 15, 2027, 7:00pm-9:00pm EST
Sep 2107:00 PM EDT
-10:00 PM EDT
Boost your GMAT score in less than one month in a live online class + 6 months access to TTP OnDemand video courses included! Class starts Mon, Tues, Wed, Thur, Fri Sept. 21, 2026 - Oct. 9, 2027, 7:00pm-10:00pm EST
28 Dec 2020, 09:00
Kudos
Bookmarks
D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
15%
(low)
Question Stats:
83% (02:27) correct
17%
(02:10)
wrong
based on 36
sessions
History
Date
Time
Result
Not Attempted Yet
In the figure below, the centers of all three circles lie on the same line. The medium-sized circle has a radius twice the size of the radius of the smallest circle, and the smallest circle has a radius whose length is 2. What is the area of the shaded region?
(A) 3π
(B) 4π
(C) 6π
(D) 8π
(E) 10π
2020-12-21_21-18-40.png [ 26.61 KiB | Viewed 2166 times ]
(A) 3π
(B) 4π
(C) 6π
(D) 8π
(E) 10π
Attachment:
2020-12-21_21-18-40.png [ 26.61 KiB | Viewed 2166 times ]
28 Dec 2020, 11:19
Kudos
Bookmarks
Given, r1= 2, r2= 4
2*R= 2*r1 + 2*r2= 2*2 +2*4, R= 6
Now, we can see area leftover(Inside Bigger circle) is symmetric in GREY and WHITE color, so area in GREY color
= {Pie (6^2) - Pie (4^2)- Pie (2^2)}/2 = 16*Pie /2 = 8*Pie
So, I think D.
2*R= 2*r1 + 2*r2= 2*2 +2*4, R= 6
Now, we can see area leftover(Inside Bigger circle) is symmetric in GREY and WHITE color, so area in GREY color
= {Pie (6^2) - Pie (4^2)- Pie (2^2)}/2 = 16*Pie /2 = 8*Pie
So, I think D.
28 Dec 2020, 21:54
Kudos
Bookmarks
\(R_s=2; R_m=4; \)
\(D_l = 2*R_s+2*R_m=2*2+4*2=12\)
\(R_l=\frac{12}{2}=6\)
By removing the smaller and medium circle area from the larger circle will help us in finding the remaining area.
Remaining \(Area = πR_l^2-(πR_m^2+πR_s^2)\)
To find the area shaded region, which is half of the remaining area. Therefore,
Shaded \(Area = \frac{πR_l^2-(πR_m^2+πR_s^2)}{2}\)
\(=π\frac{(6^2-(4^2+2^2)}{2}=π \frac{(36-20)}{2}=π\frac{16}{2}=8π\)
Ans D
\(D_l = 2*R_s+2*R_m=2*2+4*2=12\)
\(R_l=\frac{12}{2}=6\)
By removing the smaller and medium circle area from the larger circle will help us in finding the remaining area.
Remaining \(Area = πR_l^2-(πR_m^2+πR_s^2)\)
To find the area shaded region, which is half of the remaining area. Therefore,
Shaded \(Area = \frac{πR_l^2-(πR_m^2+πR_s^2)}{2}\)
\(=π\frac{(6^2-(4^2+2^2)}{2}=π \frac{(36-20)}{2}=π\frac{16}{2}=8π\)
Ans D
Attachments
Circle.jpg [ 29.27 KiB | Viewed 1937 times ]
